There are 18.9 moles in 225.8 mg. This is a math problem.
The answer is 0,615 moles.
14,84 g magnesium are equivalent to 0,61 moles.
The molar mass of oxygen is 32 g.1,2 mg oxygen is equal to 0,0000375 moles.
The number of moles in 432 g Mg (OH)2 is 7,407.
32,5 g magnesium is equal to 1,337 mol.
The answer is 0,615 moles.
14,84 g magnesium are equivalent to 0,61 moles.
The molar mass of oxygen is 32 g.1,2 mg oxygen is equal to 0,0000375 moles.
The number of moles in 432 g Mg (OH)2 is 7,407.
0,0011 moles of hydrogen are obtained.
32,5 g magnesium is equal to 1,337 mol.
3.03
Moles Mg = 3.00 g / 24.312 g/mol =0.123 Moles O2 = 2.20 / 32 g/mol = 0.0688 2 Mg + O2 >> 2 MgO the ratio between Mg and O2 is 2 : 1 0.123 / 2 = 0.0615 moles O2 needed we have 0.0688 moles of O2 so O2 is in excess and Mg is the limiting reactant we get 0.123 moles of MgO => 0.123 mol x 40.31 g/mol =4.96 g
Two moles KOH for one mole Mg(OH)2; so for 4 moles KOH - two moles Mg(OH)2.And two moles Mg(OH)2 is equal to 116,64 g.
Two moles KOH for one mole Mg(OH)2; so for 4 moles KOH - two moles Mg(OH)2.And two moles Mg(OH)2 is equal to 116,64 g.
For this you need the atomic mass of Mg. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Mg= 24.3 grams35.0 grams Mg / (24.3 grams) = 1.44 moles Mg
If you think to the mass of 88,1 moles of magnesium this is 2141,27 g.