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How many moles are in 223.2g iron (fe)?
55.8 moles
How many mole are in 223.2g iron (Fe)?
55.8 moles
How many moles are I am 223.2 g iron (Fe)?
To find the number of moles of iron (Fe) in 223.2 g, you can use the formula: moles = mass (g) / molar mass (g/mol). The molar mass of iron is approximately 55.85 g/mol. Thus, moles of iron = 223.2 g / 55.85 g/mol ≈ 3.99 moles.
How many moles are in 23 g of Fe?
To find the number of moles in 23 g of Fe, first find the molar mass of Fe by looking up the atomic weight on the periodic table. Fe has a molar mass of approximately 55.85 g/mol. Divide the given mass by the molar mass to find the number of moles: 23 g Fe / 55.85 g/mol = approximately 0.41 moles of Fe.
How many moles Fe are in a sample of Fe2O3 that contains 100g O?
To find the number of moles of Fe in Fe2O3, first calculate the molar mass of Fe2O3 and O. Then, determine the number of moles of O in the sample. Finally, you can use the stoichiometry of Fe2O3 to find the moles of Fe present. Alternatively, if you know the molar mass of just Fe, you can calculate the moles of Fe by dividing the mass of Fe in the sample by its molar mass.
How many moles are in 223.2g iron (fe)?
55.8 moles
How many mole are in 223.2g iron (Fe)?
55.8 moles
How many moles are in 233.2 g iron (Fe)?
To find the number of moles in 233.2 g of iron (Fe), you need to divide the given mass by the molar mass of iron, which is approximately 55.85 g/mol. So, 233.2 g ÷ 55.85 g/mol ≈ 4.17 moles of iron.
How many moles are in 223.2 iron (Fe)?
To determine the number of moles in 223.2 grams of iron (Fe), you will first need to divide the given mass (223.2 g) by the molar mass of iron, which is approximately 55.85 g/mol. This calculation will give you the number of moles of iron in 223.2 grams.
How many moles are I am 223.2 g iron (Fe)?
To find the number of moles of iron (Fe) in 223.2 g, you can use the formula: moles = mass (g) / molar mass (g/mol). The molar mass of iron is approximately 55.85 g/mol. Thus, moles of iron = 223.2 g / 55.85 g/mol ≈ 3.99 moles.
How many moles are present in 1.68g of iron?
To calculate the number of moles in 1.68g of iron, we need to use the molar mass of iron, which is approximately 55.85 g/mol. Divide the mass of iron (1.68g) by its molar mass to find the number of moles present. Therefore, there are approximately 0.03 moles of iron in 1.68g.
How many Fe atoms are in 0.25 moles of Fe?
To determine the number of moles of Fe that can be made from 25 moles of Fe2O3, you need to write the balanced chemical equation for producing O2 from Fe2O3. 2Fe2O3 = 4Fe + 3O2, which means that 2 moles of Fe2O3 will produce 4 moles of Fe and 3 moles of O2 . Set up a proportion. 3 moles of O2 ÷ 2 moles of Fe2O3 = x moles of O2 ÷ 25 moles of Fe2O3 Cross multiply and divide. 3 moles of O2 * 25 moles of Fe2O3 ÷ 2 moles of Fe2O3 = 37.5 moles of O2 produced.
How many moles are in 23 g of Fe?
To find the number of moles in 23 g of Fe, first find the molar mass of Fe by looking up the atomic weight on the periodic table. Fe has a molar mass of approximately 55.85 g/mol. Divide the given mass by the molar mass to find the number of moles: 23 g Fe / 55.85 g/mol = approximately 0.41 moles of Fe.
How many atoms are present in 400g Iron?
1 mole Fe = 6.022 x 1023 atoms Fe1 mole Fe = 55.845g Fe (atomic weight in grams)Convert grams Fe to moles Fe.400g Fe x (1mol Fe/55.845g Fe) = 7.16mol FeConvert moles Fe to atoms Fe.7.16mol Fe x (6.022 x 1023atoms Fe/1mol Fe) = 4.31 x 1024 atoms Fe
How many moles of iron is 5.98x1024 atoms of iron?
To find the number of moles, you need to divide the number of atoms by Avogadro's number, which is about 6.022 x 10^23 atoms/mol. So, 5.98 x 10^24 atoms of iron would be approximately 9.93 moles of iron.
How many iron atoms are contained in 354 g of iron?
There are approximately 3.25 x 10^24 iron atoms in 354 g of iron. This calculation is done by converting the mass of iron to moles using the molar mass of iron, and then using Avogadro's number to convert moles to atoms.
What is the mass of 2.25 moles of iron?
The answer is 125,65 g.
