Taking carbon @ 12.01 g/mol & hydrogen @ 1.01 g/ mol methane has 1 carbon & 4 hydrogen, so it is:
No. of moles = Given mass of element or compound/ molar mass of element or compound.
Molar mass of Methane(CH4) = 16 g
No. of moles of Methane in 345g = 345/16=21.562 moles.
it's around 67.974g, depending on how acurate the molar mass is (mine is to three decimal places)
1 mole C= 12.01 g
4 moles H= 4.04 g
Therefore, 1 mole of CH4 = 12.01g + 4.04g = 16.05g
molar mass of methane is 16g/mol
so 4 mols is 64 grams
The mass of four moles of methane is about 64g (grams).
Four moles of methane would have a mass of 64,12 grams.
First divide 4 by 16.So answer is 0.25
64 and 12 grams
Four times the atomic weight of carbon plus sixteen times the atomic weight of hydrogen = about 64 grams.
The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.
2.8 moles of gold would be 550g of gold. Multiplying the amount of moles by the molar mass (197.0 grams/moles) will give you the grams by cancelling out the moles units.
Say you have 100 grams of the compound. If so, then you would have 3.1 grams H, 31.5 grams P, and 65.4 grams O. Convert these to moles: 3.1 grams H ÷ 1.01 grams/mol = 3.07 moles H 31.5 grams P ÷ 31.0 grams/mol = 1.02 moles P 65.4 grams O ÷ 16.0 grams/mol = 4.09 moles O Divide each of these by the smallest number, which is 1.02: 3.07 ÷ 1.02 = 3 1.02 ÷ 1.02 = 1 4.09 ÷ 1.02 = 4 These are your ratios. The empirical formula is then H3PO4
Assume the compound has a molar mass of 100 grams, from the information given, 32.2 grams is Calcium and 67.8 grams is Nitrogen.You then find the moles of each, which would be moles of Ca and moles of N.Dividing the two moles gives you the mole fraction: which we approximate to 6. This means that for every 1 mole of Ca, there are 6 moles of N, thus the answer is
2344222.445
Four times the atomic weight of carbon plus sixteen times the atomic weight of hydrogen = about 64 grams.
The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.
The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.
The mass would be approximately 92 grams.
The amount of grams in two moles depends on the element or compound that you have two moles of. For example, the molar mass of oxygen is about 16 grams. So two moles of oxygen would be about 32 grams.
92
224 grams of Oxygen will be in 2 moles of Potassium dichromate.
You can only calculate the empirical formula because you do not have a mass of this compound given. To do the empirical formula assume 100 grams and change percent to grams. Get moles. 80 grams Carbon (1 mole C/12.01 grams) = 6.66 moles C 20 grams hydrogen (1 mole H/1.008 grams) = 19.84 moles H the smallest becomes 1 in the empirical formula and the other number is divided by it, Thus; H/C 19.84 moles H/6.66 moles C = 2.9, which we call 3 so, CH3 --------------- is the empirical formula To get the molecular formula tour question needed to read; How to calculate molecular formula from such ans such mass of compound with these percentages of elements, Which, of course, your question did not provide. Then you would have divided that given mass by the mass total of the elements of the empirical formula, got a whole number by which you would have multiplied the numbers of your empirical formula to get molecular formula.
You would need to know the chemiscal formal for methane, X the numbers of mole.
The mass of 2 moles of ethyl alcohol would be 92,14 grams.
2.8 moles of gold would be 550g of gold. Multiplying the amount of moles by the molar mass (197.0 grams/moles) will give you the grams by cancelling out the moles units.