978 g calcium contain 24,4 moles.
425 g calcium (Ca) is equal to 10,604 moles.
(2.7 mol Ca / 1) * (40.078 g Ca / 1 mol Ca) = 108.21 g Ca. After significant figures, the answer is 110 g Ca.
The mass of 7,346 moles of Ca(OH)2 is 544,3 g.
9 g calcium is equal to 0,224 moles.
The answer is 0,4 moles.
425 g calcium (Ca) is equal to 10,604 moles.
156 g calcium is equivalent to 3,89 moles.
0,688 g calcium is equivalent to 0,017 moles.
(2.7 mol Ca / 1) * (40.078 g Ca / 1 mol Ca) = 108.21 g Ca. After significant figures, the answer is 110 g Ca.
40 g of Ca = 1 mole So 808 g of Ca = 20.2 mole
9,0 moles of calcium is equal to 360,702 g.
12.2 g Ca/ 40.08 g/mol = .304 mol
1mol Ca = 40 gCa 45.8g/40g = 1.145 mol Ca
The mass of 7,346 moles of Ca(OH)2 is 544,3 g.
For this you need the atomic mass of Ca. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. Ca= 40.1 grams.761 moles Ca × (40.1 grams) = 30.5 grams Ca
look its easy. if you have X moles of Ca you would look it up in the elements chart and figure it out right? now all you have to do is figure out how many moles do you get of each element in the compound above and sum them up. if it still doesnt help post on my message bourd ok?
3,80 g Zn have 0,058 moles.