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To teach you how to do this problem:

1. Look at the Periodic Table. O =16 grams/mole, H =1.01 grams/mole

2. Calculate the Molecular Weight of Water. 1*O + 2*H: 16+2.02=18.02g/mole

3. Divide the mass of what you have by the Molecular Weight: 35.1g H2O/(18.02 g H2O/mole H2O)

4. The units g H2O cancel leaving you with mole H2O.

5. 35.1 grams H2O= 1.95 moles H2O

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13y ago
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15y ago

For this you need the atomic (molecular) mass of H2O. Take the number of grams and divide it by the Atomic Mass. Multiply by one mole for units to cancel. H2O=18.0 grams

85.3 grams H2O / (18.0 grams) = 4.74 moles H2O

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14y ago

75g/18gmol-1 = 4.167 moles of water molecules, composed of 4.167 moles of oxygen atoms and 8.334 moles of hydrogen atoms.

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13y ago

H=1

o=16

h2o=18

85.2/18=4.733333...

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10y ago

94.5g/18 is 5.25 moles.

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11y ago

75/18 = 4.167 moles

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Q: How many moles are in 35.1 grams of water?
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