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How many grams of O2 are in a 351 ml container that has a pressure of 12 atm at 25 Celsius?
Wiki User
∙ 9y ago
You will be using the equation for the ideal gas law: PV=nRT, where P=pressure in atm, V=volume in liters, n=moles, R=ideal gas constant (0.0821) and T=temperature in kelvins, and along the way, you must convert mL to L and Celsius to kelvins. So, plug it all in: 12atm(0.351L) = n(0.0821)(298k). The answer is 0.17mol O2, which is about 2.7g O2.
Wiki User
∙ 9y ago
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