Air is a mixture.
The answer is 0,125 moles.
0.125 moles
This is another calculation. there are 0.123 moles inn this volume.
You can use the equationPV=nRT. So there are 0.12231 moles inthat volume.
The answer is 97,66 moles.
0.125 moles
The answer is 0,125 moles.
0,125 moles
0.125 moles
This is another calculation. there are 0.123 moles inn this volume.
You can use the equationPV=nRT. So there are 0.12231 moles inthat volume.
3 (L) / 22.4 (L/mol) = 0.13 mol of any gas at STPapex- 0.125 moles
3 (L) / 22.4 (L/mol) = 0.13 mol of any gas at STPapex- 0.125 moles
The answer is 97,66 moles.
PV = nRT so --- P = nRT/V = 1.09(8.314)(293)/(2.00) = 1327.62109 kPa
1 mole is 6.022 141 293 x 1023 molecules. (Avogadro's constant). If you have 3 moles of CO2, then you have 3 x 6.022 141 293 x 1023 molecules = 1.806642388 x 1024 molecules!
Answer: 293 yd = 10,548 "