This is another calculation. there are 0.123 moles inn this volume.
The answer is 0,125 moles.
0.125 moles
Air is a mixture.
You can use the equationPV=nRT. So there are 0.12231 moles inthat volume.
You solve this using the ideal gas law: PV = nRT and solve for n (moles)n = PV/RT = (2.62 atm)(47.8 L)/(0.0821 Latm/Kmol)(775K) n = 1.97 moles (3 significant figures)
0.125 moles
The answer is 0,125 moles.
0,125 moles
0.125 moles
The number of moles is 0,579.
Air is a mixture.
hello
You can use the equationPV=nRT. So there are 0.12231 moles inthat volume.
3 (L) / 22.4 (L/mol) = 0.13 mol of any gas at STPapex- 0.125 moles
3 (L) / 22.4 (L/mol) = 0.13 mol of any gas at STPapex- 0.125 moles
You solve this using the ideal gas law: PV = nRT and solve for n (moles)n = PV/RT = (2.62 atm)(47.8 L)/(0.0821 Latm/Kmol)(775K) n = 1.97 moles (3 significant figures)
If you consider air as an ideal gas, then...n = moles = PV/RT = (1 atm)(3 L)/(0.0821 Latm/Kmole)(2933 K) n = 0.0125 moles = 0.01 moles (to 1 significant figure)