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8.32 MOLES
What else can I help you with?
How many moles are there in 500.0g of HC2H3O2?
To find the number of moles in 500.0g of HC2H3O2, divide the given mass (500.0g) by the molar mass of HC2H3O2 (60.05 g/mol). This calculation would give you approximately 8.33 moles of HC2H3O2 in 500.0g.
A solution prepared by dissolving 110 g of HC2H3O2 in 1.25 L total solution has a molarity of 1.47 M True or False?
True. To calculate the molarity, you need to divide the moles of solute by the volume of solution in liters. First, convert 110 g of HC2H3O2 to moles using its molar mass. Then, divide the moles by 1.25 L to get the molarity, which in this case is 1.47 M.
5 kilograms coverts to how many grams?
5000g
What is the Conjugate base of HC2H3O2?
The conjugate base of HC2H3O2 is C2H3O2-. This ion is formed when HC2H3O2 donates a proton.
What is 5kg converted into g?
5000g
5 kg equals how many grams?
1kg1000g so 5kg=5000g :( :| Idiots!!! ===
A student added 100 ml of 0.10 m naoh to 250 ml of a buffer that contained 0.15 m hc2h3o2 and 0.25 m c2h3o2- what is the concentration of hc2h3o2 after the addition of the strong base?
CHEM 123 Solution to Ques 16.65 from Wiley #12 16.65 A student added 100 mL of 0.10 M NaOH to 250 mL of a buffer that contained 0.15 M HC2H3O2 and 0.25 M C2H3O2−. What is the concentration of HC2H3O2 after the addition of the strong base. Begin by writing the equation for the buffer (acid dissociation of the weak acid) HC2H3O2 + H2O H3O + + C2H3O2- Ka = 1.8 × 10-5 Initial amounts in the solution are: # mol C2H3O2- = (0.25 mol/L)(0.25 L) = 0.063 mol C2H3O2- # mol HC2H3O2 = (0.15 mol/L)(0.25 L) = 0.038 mol HC2H3O2 The added base (0.100 L)(0.10 mol/L) = 0.010 mol NaOH) will react with the acetic acid present in the buffer solution: NaOH + HC2H3O2 ⎯→ H2O + NaC2H3O2 Assume the added base reacts completely (since it's a strong base with a weak acid). For each mole of base added, one mole of HC2H3O2 is converted to C2H3O2-. Since 0.010 mol of base is added, 0.010 mol of HC2H3O2 will be depleted from the initial amount (0.038 mol) and 0.010 mol C2H3O2− ADDITIONAL produced in this reaction (added to the initial amount of 0.063 mol C2H3O2−): # mol HC2H3O2final = (0.038 - 0.010) mol = 0.028 mol # mol C2H3O2-final = (0.063 + 0.010) mol = 0.073 mol The final volume of solution is 250 mL + 100 mL = 350 mL. AFTER the reaction with NaOH, the concentrations become… [HC2H3O2] = 0.028 mol/0.350L = 0.080 M HC2H3O2 [C2H3O2−] = 0.073 mol/0.350L = 0.21 M C2H3O2− In Wiley #12, the question asked only what the concentration of acetic acid becomes, so this would be the answer: 0.080 M. (The optional given you in Wiley was 0.079 M.) In the actual question in the book, it went further and asked you what is the CHANGE in concentration of HC2H3O2 and C2H3O2−, so you would simply go one further step: Initial conc of HC2H3O2 was 0.15M Change in conc = 0.15−0.080 = 0.0.07 M decrease in [HC2H3O2] Initial conc of C2H3O2− was 0.25M Change in conc = 0.25M − 0.21 Μ = 0.04 Μ decrease in [C2H3O2−]
Name of hc2h3o2?
Acetic acid
What is dose hc2h3o2 stand for?
Acetic Acid
How many moles are there in 452g of NaCl?
The answer is 7,73 moles.
How many moles of copper are in 180 grams?
2.83 moles
Which is the greater mass one fifth of 5kg or one fifth of 5000g?
one fifth
