8.32 MOLES
There are 3 carbon atoms in 1 molecule of acetic acid (HC2H3O2). Therefore, in 0.062 mol of acetic acid, there would be 0.062 x 3 = 0.186 moles of carbon atoms. To find the number of carbon atoms, you would multiply the number of moles by Avogadro's number (6.022 x 10^23) to get approximately 1.12 x 10^23 carbon atoms.
The conjugate base of HC2H3O2 is C2H3O2-. This ion is formed when HC2H3O2 donates a proton.
To find the volume of 0.258 M NaOH needed to neutralize 2.00 g of acetic acid (HC2H3O2), you can use the molar ratio between NaOH and acetic acid. First, determine the moles of acetic acid using its molar mass. Then, use the mole ratio from the balanced chemical equation to find moles of NaOH required. Finally, use the concentration of NaOH to find the volume needed.
40.00(mL)*0.10(M) = VNaOH(mL)*0.15(M) , soVNaOH(mL) = 40.00*0.10 / 0.15 = 26.67 = 27 mLCacetate = 0.10 * [ 40.00 / (40 mL + 26.7 mL) ] = 0.060 MMark: nothing to do with Kacid !
HC2H3O2 has a total of 24 valence electrons. Hydrogen contributes 1 valence electron each, carbon contributes 4, and oxygen contributes 6 each.
8.32 MOLES
5000g equates to 11.02 lbs
True. To calculate the molarity, you need to divide the moles of solute by the volume of solution in liters. First, convert 110 g of HC2H3O2 to moles using its molar mass. Then, divide the moles by 1.25 L to get the molarity, which in this case is 1.47 M.
5000g
Balanced equation: Ba(OH)2 + 2HC2H3O2 ==> 2H2O + (C2H3O2)2BaSo, the mole ratio of Ba(OH)2 to HC2H3O2 is 1:2 so it takes 1/2 as much Ba(OH)2moles Ba(OH)2 needed = 1/2 x 0.452 = 0.226 moles Ba(OH)2
There are 3 carbon atoms in 1 molecule of acetic acid (HC2H3O2). Therefore, in 0.062 mol of acetic acid, there would be 0.062 x 3 = 0.186 moles of carbon atoms. To find the number of carbon atoms, you would multiply the number of moles by Avogadro's number (6.022 x 10^23) to get approximately 1.12 x 10^23 carbon atoms.
There is only one equivalent of OH^-1 in one molecule of HC2H3O2.
8kg is 3kg larger than 5000g (5kg)
5000g equates to about 11 (11.02311) pounds.
The conjugate base of HC2H3O2 is C2H3O2-. This ion is formed when HC2H3O2 donates a proton.
To find the volume of 0.258 M NaOH needed to neutralize 2.00 g of acetic acid (HC2H3O2), you can use the molar ratio between NaOH and acetic acid. First, determine the moles of acetic acid using its molar mass. Then, use the mole ratio from the balanced chemical equation to find moles of NaOH required. Finally, use the concentration of NaOH to find the volume needed.
5000g