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1 mole of NaHCO3
Na = 1 * 22.99 g = 22.99 g
H = 1 * 1.01 g = 1.01 g
C = 1 * 12.01 g = 12.01 g
O = 3 * 16.00 g = 48.00 g
Total = 84.01 g
There are 84.01 grams in one mole of NaHCO3.
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How many moles are contained in 86.6 grams in sodium bicarbonate?
Sodium Bicarbonate = NaHCO3 Molecular weight = Summation of individual molecular weights of elements =[(1)(22.99 g/mol) ] + [(1)(1.01 g/mol)] + [(1)(12.01 g/mol)] + [(3)(15.99 g/mol)] =84.01 g/molSo,(86.6 g) / (84.01 g/mol) = 1.031 mol
What is 2.00 grams of baking soda in moles?
Remember moles = mass(g) / Mr The 'Mr' is the relative molecular mass. The Mr(Baking soda ; sodium hydrogen carbonate ; NaHCO3) is Na x 1 = 23 x 1 = 23 H x 1 = 1 x 1 = 1 C x 1 = 12 x 1 = 12 O x 3 = 16 x 3 = 48 23 + 1 + 12 + 48 = 84 ( Mr of NaHCO3) Hence mol(NaHCO3) = 2.00g / THe answers!!!!!
How many moles of NaHCO3 are present in 3.00 g sample?
3.00 grams NaHCO3 (1 mole/84.008 grams) = 0.0357 moles of sodium bicarbonate
How do you prepare 500cm3 of NaHCO3 solution of 1M concentration?
Weighting half value of 23+1+12+(3x16) = 84/2 = 42 gram NaHCO3 gives you 0.5 mole of it, to be dissolved in about 200 mL and there after to be filled up to 500 mL (= 500 cm3) will result in a 0.5 mol / 500 mL = 0.5 mol / 0.5 L = 1 mol/L = 1M NaHCO3
What is the mass of 42.6 mol of Si?
1196.4423g 42.6 mol X 28.0855 g/ 1 mol = 1196.4423g
What is the solute mass of NaHCO3 if mol solute is 0.025 volume solution is 0.25 liters and molarity 0.100M?
All you need is the moles and the mass of NaHCO3 and you have the moles 0.025 moles NaHCO3 (84.008 grams/1 mole NaHCO3) = 2.1 grams of sodium bicarbonate ---------------------------------------------
How many moles of NaHCO3 are present in a 6.10 g sample?
Divide 6.10 (g NaHCO3) by 84.007 (g.mol−1 NaHCO3) to get 0.0726 mol NaHCO3
How many moles are contained in 86.6 grams in sodium bicarbonate?
Sodium Bicarbonate = NaHCO3 Molecular weight = Summation of individual molecular weights of elements =[(1)(22.99 g/mol) ] + [(1)(1.01 g/mol)] + [(1)(12.01 g/mol)] + [(3)(15.99 g/mol)] =84.01 g/molSo,(86.6 g) / (84.01 g/mol) = 1.031 mol
What is 2.00 grams of baking soda in moles?
Remember moles = mass(g) / Mr The 'Mr' is the relative molecular mass. The Mr(Baking soda ; sodium hydrogen carbonate ; NaHCO3) is Na x 1 = 23 x 1 = 23 H x 1 = 1 x 1 = 1 C x 1 = 12 x 1 = 12 O x 3 = 16 x 3 = 48 23 + 1 + 12 + 48 = 84 ( Mr of NaHCO3) Hence mol(NaHCO3) = 2.00g / THe answers!!!!!
How many moles of NaHCO3 are present in 3.00 g sample?
3.00 grams NaHCO3 (1 mole/84.008 grams) = 0.0357 moles of sodium bicarbonate
How many moles does 26.35 grams of iridium have?
1 Mol
What mass of NaHCO3 is needed to neutralize 150ml of 044M HCl?
Several part problem. Get molarity of NaHCO3. (150 ml)( M NaHCO3) = (150 ml)(0.44 M HCl) = 0.44 M NaHCO3 --------------------------- get moles NaHCO3 ( 150 ml = 0.150 Liters ) 0.44 M NaHCO3 = moles NaHCO3/0.150 Liters = 0.066 moles NaHCO3 ---------------------------------------get grams 0.066 moles NaHCO3 (84.008 grams/1 mole NaHCO3) = 5.54 grams NaHCO3 needed ---------------------------------------------answer
How do you prepare 500cm3 of NaHCO3 solution of 1M concentration?
Weighting half value of 23+1+12+(3x16) = 84/2 = 42 gram NaHCO3 gives you 0.5 mole of it, to be dissolved in about 200 mL and there after to be filled up to 500 mL (= 500 cm3) will result in a 0.5 mol / 500 mL = 0.5 mol / 0.5 L = 1 mol/L = 1M NaHCO3
What is the mass of 42.6 mol of Si?
1196.4423g 42.6 mol X 28.0855 g/ 1 mol = 1196.4423g
How many grams are in 0.577 mol Na2CO3?
1 mole Na2CO3 = 105.98844g 0.577mol x 105.98844g/mol = 61.2g Na2CO3
How many grams of alcl3 are produced from with 8.0 moles of al2o3. 6cl2 plus 2al2o3 equals 3o2 plus 4alcl3 equals?
8 mol x (4 mol / 2 mol) x 133.5 g / 1 mol = 2136 grams
How many atoms are in 0.0010 grams of calcium?
(g) -> moles = x(g) * (1 mol/molar mass)Moles -> atoms = x(mol) * (6.022*10^23/1 mol)
