Weighting half value of 23+1+12+(3x16) = 84/2 = 42 gram NaHCO3 gives you 0.5 mole of it, to be dissolved in about 200 mL and there after to be filled up to 500 mL (= 500 cm3) will result in a 0.5 mol / 500 mL = 0.5 mol / 0.5 L = 1 mol/L = 1M NaHCO3
5M NaHCO3 is more concentrated than 5 percent NaHCO3. Molarity (M) measures the concentration of a solution based on the number of moles of solute per liter of solution, whereas percent concentration is based on the mass of the solute per 100 parts of the total solution.
To prepare 50 ml of a 1.0 M NaHCO3 solution from a 2.5 M stock solution, she would need to mix 10 ml of the 2.5 M solution with 40 ml of water. This dilution would result in a final concentration of 1.0 M.
Sodium bicarbonate, NaHCO3 is alkaline so the pH will be greater than 7. However, the actual pH will depend on the concentration of the NaHCO3 solution.
Yes, an aqueous solution of NaHCO3 (sodium bicarbonate) is slightly basic.
Yes, sodium bicarbonate (NaHCO3) is soluble in water and forms an aqueous solution.
5M NaHCO3 is more concentrated than 5 percent NaHCO3. Molarity (M) measures the concentration of a solution based on the number of moles of solute per liter of solution, whereas percent concentration is based on the mass of the solute per 100 parts of the total solution.
To prepare 50 ml of a 1.0 M NaHCO3 solution from a 2.5 M stock solution, she would need to mix 10 ml of the 2.5 M solution with 40 ml of water. This dilution would result in a final concentration of 1.0 M.
Sodium bicarbonate, NaHCO3 is alkaline so the pH will be greater than 7. However, the actual pH will depend on the concentration of the NaHCO3 solution.
Yes, an aqueous solution of NaHCO3 (sodium bicarbonate) is slightly basic.
500 mL * 100(mMol/mL) = 50 mMol NaHCO3 , hence50 mMol NaHCO3 = 50(mMol) * 84(mg/mMol) = 4200 mg = 4.2 g NaHCO3 in 500 mL
Yes, sodium bicarbonate (NaHCO3) is soluble in water and forms an aqueous solution.
NaHCO3 (Sodium bicarbonate) [at room temperature] will produce a pH of around 8.
You would add a weak acid, like acetic acid (CH3COOH), to NaHCO3(aq) to form a buffer solution. The weak acid will react with the bicarbonate ion in NaHCO3 to maintain a stable pH.
The answer is 5 m L sodium bicarbonate, 1 M solution.
NaHCO3 is sodium bicarbonate (baking soda.) It is water soluble, and in solution it will dissociate into Na+ ions and HCO3- ions.
The solution must contain Na2CO3 and NaHCO3.
for 500ml 0,05M solution take Na2CO3#1.59gm NaHCO3#2.93 ph#9.6