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5 M NaHCO3

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14y ago

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Is 5m HCl a concentrated weak acid?

Yes, 5M HCl is considered a concentrated strong acid. Hydrochloric acid is a strong acid that fully dissociates in water to produce hydrogen ions. The high concentration of 5M indicates a large number of hydrogen ions available in the solution.


5 N H2SO4 What is percent?

To calculate the percent of a 5 N H2SO4 solution, you need to know the molarity (moles of solute per liter of solution) and the molecular weight of the solute. Once you have that information, you can use the formula: % = (molarity x equivalent weight) / 10. If you provide the molecular weight of H2SO4, I can help you calculate the percent.


How many milliliters of 3M phosphoric acid H3PO4 can be made from 95ml of a 5M H3PO4 solution?

To determine the volume of 3M phosphoric acid that can be made from a 5M solution, you can use the formula M1V1 = M2V2. Plug in the values: M1 = 5M, V1 = 95ml, M2 = 3M. Then solve for V2. Convert the units accordingly to obtain the volume of 3M phosphoric acid that can be made.


How much amount of 5M sulfuric acid needed for the preparation of 0.002M of 1500ml?

To prepare a 0.002M solution in 1500 ml, you would need to use the formula: M1V1 = M2V2. Given that M1 = 5M, V1 = unknown, M2 = 0.002M, and V2 = 1500 ml, you can solve for V1 which will give you the volume of the 5M sulfuric acid needed.


What volume of a 3m koh solution can be prepared by diluting 0.5 l of a 5m koh solution?

To dilute the 5M KOH solution to 3M, we can use the formula: M1V1 = M2V2, where M1 = initial molarity, V1 = initial volume, M2 = final molarity, and V2 = final volume. Plugging in the values, we get: (5M)(0.5L) = (3M)(V2). Solving for V2 gives V2 = 0.5 * 5 / 3 = 0.833 L. So, 0.833 liters of 3M KOH solution can be prepared by diluting 0.5L of 5M KOH solution.