1 mole Na2CO3 = 105.98844g
0.577mol x 105.98844g/mol = 61.2g Na2CO3
0.277 mole Na2CO3 x 106 g/mole = 29.4 g (to 3 significant figures)
6into23equals 138 6into23equals 138
Na2CO32 * 2 = 4 moles sodium.===========================
the answer to your question is 0.0004 g/mol.
The AR (atomic mass) of CO2 (carbon dioxide) is 44 g/mol. The MR (molar mass) of Na2CO3 (sodium carbonate) is 106 g/mol.
0.277 mole Na2CO3 x 106 g/mole = 29.4 g (to 3 significant figures)
To determine how many moles of Na2CO3 are used, you need to know the molar mass of Na2CO3. It is 105.99 g/mol. Then, you can calculate the number of moles using the given mass: mass in grams / molar mass = moles of Na2CO3.
6into23equals 138 6into23equals 138
Write out the equation, and remember to balance each side.Na2CO3 + Ca(OH)2 --> 2NaOH + CaCO3Molecular WeightsNa2CO3: 106 grams/moleNaOH: 40 grams/moleAlways convert your reagents into moles.(120g Na2CO3) x (1 mole Na2CO3/106 grams Na2CO3) = 1.132 molesAccording to the balanced equation, 1 molecule of Na2CO3 generates 2 molecules of NaOH.(1.132 moles Na2CO3) x (2 moles NaOH/1 mole Na2CO3) = 2.264 moles NaOHNow determine the number of grams from 2.264 moles of NaOH.(2.264 moles NaOH) x (40 grams/ 1 mole NaOH) = 90.57 grams NaOH formed.To prevent rounding off too many times, carry out the dimensional analysis in one step:(120g Na2CO3) x (1 mole Na2CO3/106 grams Na2CO3) x(2 moles NaOH/1 mole Na2CO3) x (40 grams/ 1 mole NaOH) = 90.57 grams NaOH
Na2CO32 * 2 = 4 moles sodium.===========================
the answer to your question is 0.0004 g/mol.
Washing soda is sodium carbonate, Na2CO3. Using the atomic weights from the periodic table and the subscripts in the formula, the molar mass of Na2CO3 = 106g/mol. 5g Na2CO3 x (1mol Na2CO3/106g/mol) = 0.05mol Na2CO3
The AR (atomic mass) of CO2 (carbon dioxide) is 44 g/mol. The MR (molar mass) of Na2CO3 (sodium carbonate) is 106 g/mol.
To find the mass of 0.893 moles of Na₂CO₃, we first calculate its molar mass. The molar mass of Na₂CO₃ (sodium carbonate) is approximately 105.99 g/mol. Therefore, the mass can be calculated using the formula: mass = moles × molar mass, which gives us 0.893 mol × 105.99 g/mol = 94.55 grams. Thus, 0.893 moles of Na₂CO₃ corresponds to approximately 94.55 grams.
The molar mass of Na2CO3 is 106 g/mol. The molar mass of sodium in Na2CO3 is 2 * 23 g/mol = 46 g/mol. To calculate the mass percent of sodium in Na2CO3, we divide the molar mass of sodium by the molar mass of Na2CO3 and multiply by 100: (46 g/mol / 106 g/mol) * 100 ≈ 43.4%.
92.4 grams
The answer is 0,3422 grams.