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How many grams HBr are required to produce 150g AlBr3 in the equation 2Al plus 6HBr producing 2AlBr3 and 3H2?
Given the balanced equation2Al + 6HBr --> 2AlBr3 + 3H2In order to find how many grams of HBr are required to produce 150g AlBr3, we must convert from mass to mass (mass --> mass conversion).150g AlBr3 * 1 mol AlBr3 * 6 molecules HBr = 136.52 or 137g HBr----------- 266.6g AlBr3 * 2 molecules AlBr3
How many grams of co2 are in 2l mol of the compound?
92.4 grams
How many grams are present in 0.20 mol of Na?
To determine the number of grams present in 0.20 mol of Na, you need to use the molar mass of sodium, which is approximately 23 grams/mol. Therefore, 0.20 mol of Na is equal to 0.20 mol x 23 g/mol = 4.6 grams of Na.
How many grams of Mn are in 4.0 mol of the element?
To find the grams of Mn in 4.0 mol, you would first determine the molar mass of Mn (54.94 g/mol) and then multiply by the number of moles given (4.0 mol). This calculation would give you 219.76 grams of Mn.
How many grams is 0.894 mol?
This depends on the chemical compound.
How many moles are in 186 grams of HBr?
For this you need the atomic (molecular) mass of HBr. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. HBr= 81.0 grams186 grams HBr / (81.0 grams) =2.30 moles HBr
How many kilojoules are associated with the formation of 2 moles of HBr?
The standard enthalpy of formation of HBr is -36.3 kJ/mol. For 2 moles of HBr, the total energy associated with the formation would be: -36.3 kJ/mol * 2 mol = -72.6 kJ.
How many atoms are in 2.13 grams of HBr?
To find the number of atoms in 2.13 grams of HBr, you first need to determine the number of moles using the molar mass of HBr (molar mass = 80.91 g/mol). Then, you can use Avogadro's number (6.022 × 10^23 atoms/mol) to convert moles to atoms.
What minimum mass of HCl in grams would you need to dissolve a 2.2 g iron bar on a padlock?
3.8 g Fe * 1 mol Fe/55.85 g Fe (molar mass) = .0680 mol Fe .0680 mol Fe * 2 mol HBr/1 mol Fe (found in formula Fe+2HBr=>FeBr2+H2)=.136 mol HBr .136 mol HBr*80.912 g HBr/1 mol HBr=11.004 g HBr (or 11 using 2 sig figs) And the mass of H2 that is produced is 0.14 g
How many grams HBr are required to produce 150g AlBr3 in the equation 2Al plus 6HBr producing 2AlBr3 and 3H2?
Given the balanced equation2Al + 6HBr --> 2AlBr3 + 3H2In order to find how many grams of HBr are required to produce 150g AlBr3, we must convert from mass to mass (mass --> mass conversion).150g AlBr3 * 1 mol AlBr3 * 6 molecules HBr = 136.52 or 137g HBr----------- 266.6g AlBr3 * 2 molecules AlBr3
What is the mass of HBr gas when excess H gas and 1.25 mol of Br gas react?
To determine the mass of HBr gas formed, you first need to find the limiting reactant. Once you determine that, you can calculate the amount of HBr produced using the stoichiometry of the reaction and then convert it to mass using the molar mass of HBr. Without the balanced chemical equation, it is not possible to provide an exact mass calculation.
How many kilo-joules are associated with the formation of 2 moles of HBr(g)?
The standard enthalpy of formation of HBr(g) is -36.2 kJ/mol. For 2 moles of HBr(g), the total energy associated with its formation would be 2 * -36.2 kJ/mol = -72.4 kJ.
How many moles are present in 1.21 molecules of HBr?
To find the number of moles in 1.21 molecules of HBr, divide the number of molecules by Avogadro's number (6.022 x 10^23 molecules/mol). Thus, 1.21 molecules of HBr is approximately 2.01 x 10^-24 moles.
How many grams of co2 are in 2l mol of the compound?
92.4 grams
How many grams are present in 0.20 mol of Na?
To determine the number of grams present in 0.20 mol of Na, you need to use the molar mass of sodium, which is approximately 23 grams/mol. Therefore, 0.20 mol of Na is equal to 0.20 mol x 23 g/mol = 4.6 grams of Na.
How many grams of ccl4 are needed to have 5.000 mol?
To find the grams of CCl4 needed, multiply the number of moles (5.000 mol) by the molar mass of CCl4 (153.82 g/mol). (5.000 , \text{mol} \times 153.82 , \text{g/mol} = 769.1 , \text{g}) Therefore, 769.1 grams of CCl4 are needed.
How many grams are 3 mol of KBr?
357
