2.13 g (6.02 x 1023 atoms) / (1.01 + 79.91) = 1.58 x 1022 atoms
The balanced chemical equation is: 6HBr + Al2(SO4)3 -> 2AlBr3 + 3SO3 + 6H2O. To find the grams of aluminum bromide formed, you need to calculate the molar ratio of HBr to AlBr3 and then convert 121g of HBr to grams of AlBr3.
The chemical symbol for hydrogen bromide is HBr.
The chemical formula of hydrogen bromide is HBr.
HBr In a chemical equation you would write it as HBr(aq).
To find the number of moles in 1.21 molecules of HBr, divide the number of molecules by Avogadro's number (6.022 x 10^23 molecules/mol). Thus, 1.21 molecules of HBr is approximately 2.01 x 10^-24 moles.
For this you need the atomic (molecular) mass of HBr. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. HBr= 81.0 grams186 grams HBr / (81.0 grams) =2.30 moles HBr
The answer is 0,3422 grams.
The balanced chemical equation is: 6HBr + Al2(SO4)3 -> 2AlBr3 + 3SO3 + 6H2O. To find the grams of aluminum bromide formed, you need to calculate the molar ratio of HBr to AlBr3 and then convert 121g of HBr to grams of AlBr3.
There is one hydrogen atom and one bromine atom in one molecule of HBr.
Yes, HBr is a molecular compound. It consists of covalent bonds between hydrogen and bromine atoms, forming molecules of HBr.
HF is the least polar among these molecules because it has the smallest difference in electronegativity between the hydrogen and the fluorine atoms.
Given the balanced equation2Al + 6HBr --> 2AlBr3 + 3H2In order to find how many grams of HBr are required to produce 150g AlBr3, we must convert from mass to mass (mass --> mass conversion).150g AlBr3 * 1 mol AlBr3 * 6 molecules HBr = 136.52 or 137g HBr----------- 266.6g AlBr3 * 2 molecules AlBr3
HBr is a polar covalent bond because hydrogen and bromine have different electronegativities, leading to an unequal sharing of electrons between the two atoms.
As it is a diatomic molecule it can only be linear.
Yes, HBr is a polar molecule with a significant difference in electronegativity between hydrogen and bromine atoms. This results in a permanent dipole moment, making it exhibit dipole-dipole interactions with other polar molecules.
This is a titration question: we want to have the same number of hydroxide ions as hydroxide ions so that they will form water and the pH will be neutral. In chemistry, we count atoms and molecules in moles, and we can calculate how many moles of HBr we have, because concentration in molarity is the number of moles divided by the volume in liters... M = moles/V. We plug in what we got: 1.45M = moles/0.0350L, and solve for moles: 0.0508 moles. Now we know we need 0.0508 moles of NaOH, whose molecular weight is 40g/mole. MW x moles = grams, so (40g/mole)(0.0508 moles) = 2.03 g of NaOH.
how many planets are there? how many planets are there? how many planets are there?