2.13 g (6.02 x 1023 atoms) / (1.01 + 79.91) = 1.58 x 1022 atoms
133
2.01 mol
HBr In a chemical equation you would write it as HBr(aq).
This does not make a buffer because HBr is a STRONG acid, and for a buffer you need a WEAK acid and the salt of the acid.
Considering conservation of mass, the mass will not be destroyed or gained. This means that there will be 20 grams of hydrogen flouride.
For this you need the atomic (molecular) mass of HBr. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. HBr= 81.0 grams186 grams HBr / (81.0 grams) =2.30 moles HBr
The answer is 0,3422 grams.
3 There are 2 For hydrogen and 1 for Br
133
Given the balanced equation2Al + 6HBr --> 2AlBr3 + 3H2In order to find how many grams of HBr are required to produce 150g AlBr3, we must convert from mass to mass (mass --> mass conversion).150g AlBr3 * 1 mol AlBr3 * 6 molecules HBr = 136.52 or 137g HBr----------- 266.6g AlBr3 * 2 molecules AlBr3
3.21 moles HBr (6.022 X 10^23/1mole HBr) = 1.93 X 10^24 molecules of HBr
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HBr
They are both linear, because both have only two atoms. HBr is more polar than br2, because H and Br are different atoms. So, the bond is polar, given that H and Br have differing capacities to attract electrons
HBr is covalent as the difference in electronegativity between the two atoms is less than 1.7
HBr has a dipole
yes HBr is an electrolyte