This depends on the chemical compound.
92.4 grams
The answer is 0,3422 grams.
To determine the number of grams present in 0.20 mol of Na, you need to use the molar mass of sodium, which is approximately 23 grams/mol. Therefore, 0.20 mol of Na is equal to 0.20 mol x 23 g/mol = 4.6 grams of Na.
To find the grams of Mn in 4.0 mol, you would first determine the molar mass of Mn (54.94 g/mol) and then multiply by the number of moles given (4.0 mol). This calculation would give you 219.76 grams of Mn.
I think 92.4 grams
92.4 grams
The answer is 0,3422 grams.
To determine the number of grams present in 0.20 mol of Na, you need to use the molar mass of sodium, which is approximately 23 grams/mol. Therefore, 0.20 mol of Na is equal to 0.20 mol x 23 g/mol = 4.6 grams of Na.
To find the grams of CCl4 needed, multiply the number of moles (5.000 mol) by the molar mass of CCl4 (153.82 g/mol). (5.000 , \text{mol} \times 153.82 , \text{g/mol} = 769.1 , \text{g}) Therefore, 769.1 grams of CCl4 are needed.
357
To find the grams in 4.20 mol of sodium chloride, you need to calculate the molar mass of sodium chloride (NaCl), which is approximately 58.44 g/mol. Multiply this molar mass by 4.20 mol to get the grams: 58.44 g/mol * 4.20 mol = 245.808 g. Therefore, 4.20 mol of sodium chloride would be approximately 245.808 grams.
To convert moles to grams, you need to use the molar mass of NaCl. The molar mass of NaCl is approximately 58.44 g/mol. Therefore, 1.6 mol of NaCl would be equal to 1.6 mol * 58.44 g/mol = 93.504 grams of NaCl.
To find the grams of Mn in 4.0 mol, you would first determine the molar mass of Mn (54.94 g/mol) and then multiply by the number of moles given (4.0 mol). This calculation would give you 219.76 grams of Mn.
To find the grams in 0.644 mol of oxygen, you need to multiply the number of moles by the molar mass of oxygen. The molar mass of oxygen is approximately 16 g/mol. Therefore, 0.644 mol of oxygen would contain 0.644 mol x 16 g/mol = 10.304 grams of oxygen.
There are 9.3504 grams of Sodium Chloride. Calculations: 0.160 mol NaCl (58.44g/mol) = 9.3504g NaCl
I think 92.4 grams
5.25 grams Ba(OH)2 (1mol Ba(OH)2/171.316 grams Ba(OH)2 ) = 0.0306 moles Ba(OH)2