6into23equals 138 6into23equals 138
3 x 2 x 23 = 138g
one mole sodium carbonate contains 23X2 sodium, for three moles it will be 23X2X3=138 gram;
3 moles of sodium carbonate (Na2CO3) contain 6 moles of sodium ions (2 sodium ions per molecule of sodium carbonate). The molar mass of sodium is 23 g/mol, so 6 moles of sodium is approximately 138 grams in total.
To convert moles to grams, you need to multiply the number of moles by the molar mass of the substance. The molar mass of Na2CO3 (sodium carbonate) is 105.99 g/mol. So, to find the grams in 0.577 mol of Na2CO3, you would calculate 0.577 mol * 105.99 g/mol = approximately 60.98 grams of Na2CO3.
The balanced equation for the reaction between sodium carbonate (Na2CO3) and hydrochloric acid (HCl) is: Na2CO3 + 2HCl -> 2NaCl + H2O + CO2 This equation shows that one mole of sodium carbonate reacts with two moles of hydrochloric acid to produce two moles of sodium chloride, water, and carbon dioxide.
3 x 2 x 23 = 138g
To determine the number of moles of sodium carbonate in 2 grams of hydrated sodium carbonate, we first need to calculate the molar mass of Na2CO3·xH2O. Once we have the molar mass, we can use the formula: Moles = Mass / Molar mass. Given that hydrated sodium carbonate has the molar mass of Na2CO3·xH2O, we can determine the number of moles in 2 grams of the compound.
3 moles of sodium carbonate (Na2CO3) contain 6 moles of sodium ions (Na). Since the molar mass of sodium is about 23 g/mole, there would be approximately 138 grams of sodium in 3 moles of sodium carbonate.
one mole sodium carbonate contains 23X2 sodium, for three moles it will be 23X2X3=138 gram;
My Shaft
3 moles of sodium carbonate (Na2CO3) contain 6 moles of sodium ions (2 sodium ions per molecule of sodium carbonate). The molar mass of sodium is 23 g/mol, so 6 moles of sodium is approximately 138 grams in total.
Balanced equation always first!! Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O Find moles HCl by---Molarity = moles of solute/Liters of solution (18.1 ml = 0.0181 L) 0.23 M HCl = moles HCl/0.0181 liters = 0.004163 moles HCl Drive back against sodium carbonate stoichometrically 0.004163 moles HCl (1 mole Na2CO3/2 mole HCl)(105.99 grams/1 mole Na2CO3) = 0.22 grams Na2CO3 needed --------------------------------------------
Write out the equation, and remember to balance each side.Na2CO3 + Ca(OH)2 --> 2NaOH + CaCO3Molecular WeightsNa2CO3: 106 grams/moleNaOH: 40 grams/moleAlways convert your reagents into moles.(120g Na2CO3) x (1 mole Na2CO3/106 grams Na2CO3) = 1.132 molesAccording to the balanced equation, 1 molecule of Na2CO3 generates 2 molecules of NaOH.(1.132 moles Na2CO3) x (2 moles NaOH/1 mole Na2CO3) = 2.264 moles NaOHNow determine the number of grams from 2.264 moles of NaOH.(2.264 moles NaOH) x (40 grams/ 1 mole NaOH) = 90.57 grams NaOH formed.To prevent rounding off too many times, carry out the dimensional analysis in one step:(120g Na2CO3) x (1 mole Na2CO3/106 grams Na2CO3) x(2 moles NaOH/1 mole Na2CO3) x (40 grams/ 1 mole NaOH) = 90.57 grams NaOH
To find how many grams of sodium carbonate contain 1.773 x 10^17 carbon atoms, you need to consider the molar ratio. Sodium carbonate (Na2CO3) has 1 carbon atom per molecule. Calculate the molar mass of Na2CO3, then use Avogadro's number to convert the number of carbon atoms to moles, and finally to grams.
To find the number of moles in 4g of sodium carbonate, first calculate the molar mass of sodium carbonate (Na2CO3), which is 105.99 g/mol. Then, divide the given mass by the molar mass to get the number of moles. Therefore, 4g of sodium carbonate is equivalent to approximately 0.038 moles.
To find the number of moles in 2.12g of sodium carbonate, you first need to determine the molar mass of Na2CO3 (105.99 g/mol). Then, divide the given mass by the molar mass to get the number of moles. In this case, 2.12g / 105.99 g/mol ≈ 0.02 moles of sodium carbonate.
To convert moles to grams, you need to multiply the number of moles by the molar mass of the substance. The molar mass of Na2CO3 (sodium carbonate) is 105.99 g/mol. So, to find the grams in 0.577 mol of Na2CO3, you would calculate 0.577 mol * 105.99 g/mol = approximately 60.98 grams of Na2CO3.