0
What else can I help you with?
What is the percentage concentration of a 0.1N sodium hydoxide solution?
Mol mass of NaOH is about 40g/mol 0.1N is same as 0.1M means 0.1mol/L 0.1mol = 0.1mol x 40g/mol = 4g so 0.1M means 4g of NaOH in 1L of water (0.1N = 0.1M = 0.1mol/L = 4g/L) 4g/L is 0.4%
How many grams of sodium hydroxide must be dissolve in 200 g of water to produce a 4.00 percent by mass aqueous sodium hydroxide solution?
4.00% (percent) by mass (weight) means 4.00g for each 100g of solution. There are 2 x 100g of water, so 2 x 4g =8.00g of NaOH (sodium hydroxide) But, a 4% aqueous solution of NaOH should mean it's 96% (96g) water. There are 2.08333 x 96g of water, so 2.08333 x 4g = 8.33g of NaOH.
How many oxygen molecules are there in in 4 g of oxygen?
Assuming you mean oxygen gas, the number of molecules can be found by first finding the number of moles = mass of oxygen (4g) / Molecular mass of oxygen gas (32 g mol-1) This tells us there is 0.125 mol of oxygen gas present. The number of molecules present is given by the number of moles x the avogadro constant (6.022x10^23) So the number of oxygen gas molecules present is equal to 0.125 x 6.022x10^23 = 7.5275x10^22 molecules
How do you prepare a 500mL of 1M of NaCl solutuion?
If you need to make just 100mL, then you need 1 tenth of a liter that is 5M. If you were to make 1L of 5 molar NaCl, you would need 5 times the molar mass of NaCl (58.44g/mol) dissolved in 1L of water. Thus for 1L of a 5M solution you need 5 * 58.44g, or 292.2 grams of NaCl. However, since we only want 100mL, which is 1/10 of a Liter, we also only need 1/10 the amount of NaCl, or 292.2 / 10, which is 29.22g. So, measure out 29.22g NaCl, and dissolve completly in a volume less than 100mL, say 80mL, then bring the final volume up to 100mL. You now have 100mL of a 5M NaCl solution.
How much cesium would remain from a 10 g sample after 6 years?
After 6 years, approximately 5 grams of cesium-137 would remain from a 10 g sample due to its half-life of around 30 years. This decay is exponential, with about half of the original sample decaying every 30 years.
How many moles are there in 4g of sodium?
To determine the number of moles in 4g of sodium, you need to divide the given mass by the molar mass of sodium. The molar mass of sodium is 22.99 g/mol. Therefore, 4g of sodium is equal to 0.174 moles.
How many moles are present in 4g sodium hydroxide?
To determine the number of moles in 4g of sodium hydroxide (NaOH), divide the mass by the molar mass of NaOH. The molar mass of NaOH is approximately 40g/mol (Na = 23g/mol, O = 16g/mol, H = 1g/mol). Therefore, 4g of NaOH is equal to 0.1 moles.
calculate the number of moles in H2 molecules in 4g H2?
2 moles.
How many moles are in 30.8g of helium?
4 g of He = 1 mole. So, 30.8 g = 7.7 moles
How many grams are in 5.82 moles of helium?
There are 23.28 grams in 5.82 moles of helium, because 5.82 mol times 4g =23.28 grams
How many moles of heLium are contained in 0.255g of helium?
use this formula, n(He)=m(He)/M(molar mass of He) =0.255G/4.OO =0.06375 moles per gram.
How many moles are present in 0.12g of helium?
To calculate the number of moles in 0.12g of helium, you need to use the molar mass of helium. The molar mass of helium is approximately 4g/mol. Therefore, 0.12g of helium is equivalent to 0.12g / 4g/mol = 0.03 moles of helium.
How much sodium is found in the blood?
a typical person's blood has about 4g of salt
How many moles in 4gram of oxygen?
1 mole O = 15.9994g 4g O x 1mol/15.9994g = 0.3mol O (rounded to 1 significant figure)
How many moles of Helium are in 6.46 g of Helium?
Helium is 4g/mol, so 6.46g of helium is 6.46/4=1.62 moles He.
Why was there no increase in reaction with 8g compared to 4g of substrate?
Generally, if you increase a reagent and there is no increase in the reaction, then it is limited by the amount of another reagent present. For example, a mole of Sodium Hydrogen Carbonate will react with a mole of Acetic Acid. However, doubling the Acetic acid will not result in a greater reaction because it is limited by the amount of Sodium Hydrogen Carbonate present.
How do you convert 26.7kg of helium into moles of helium?
To convert grams to moles, divide the given mass by the molar mass of helium. The molar mass of helium is approximately 4g/mol. Therefore, 26.7kg of helium is equal to 26,700g, which would be 6,675 moles of helium.
