This is a chemical calculation. 2.5 moles will C reacting with O2.
6 moles
5.0 grams CO2 (1mol CO2/44.01g) = 0.11 moles CO2
Balanced equation first, 2C6H14 + 19O2 >> 12CO2 + 14H2O 84.4 moles hexane (12 moles CO2/2 moles C6H14) = 506.4 moles of CO2
Given the balanced equation2C3H8O + 9O2 --> 6CO2 + 8H2OTo find the number of moles CO2 that will be produced from 0.33 mol C3H8O, we must convert from moles to moles (mol --> mol conversion).0.33 mol C3H8O * 6 molecules CO2 = 0.99 mol CO2---------- 2 molecules C3H8O
Balanced equation. CH4 + 2O2 -> CO2 + 2H2O one to one, but set-up anyway and limiting reacting known 2.0 moles CH4 (1 mole CO2/1 mole CH4) = 2.0 moles CO2 produced ( by the way, those numbers are subscripts, not superscripts )
How many moles of CO2 are produced when 2.1 mol of C2H2 react?
6 moles
5.0 grams CO2 (1mol CO2/44.01g) = 0.11 moles CO2
Balanced equation first, 2C6H14 + 19O2 >> 12CO2 + 14H2O 84.4 moles hexane (12 moles CO2/2 moles C6H14) = 506.4 moles of CO2
CO2 + 4H2 --> CH4 + 2H2O0.500 moles CO2 (1 mole CH4/1 mole CO2) = 0.500 moles CH40.500 moles CO2 (2 moles H2O/1 mole CO2) = 1.00 moles H2O-------------------------------------------------------------------------------------add= 1.50 moles total product====================
11,2 moles carbon dioxide are obtained.
Given the balanced equation2C3H8O + 9O2 --> 6CO2 + 8H2OTo find the number of moles CO2 that will be produced from 0.33 mol C3H8O, we must convert from moles to moles (mol --> mol conversion).0.33 mol C3H8O * 6 molecules CO2 = 0.99 mol CO2---------- 2 molecules C3H8O
Balanced equation. CH4 + 2O2 -> CO2 + 2H2O one to one, but set-up anyway and limiting reacting known 2.0 moles CH4 (1 mole CO2/1 mole CH4) = 2.0 moles CO2 produced ( by the way, those numbers are subscripts, not superscripts )
Also 0,1 mole carbon dioxide.
First write the balance equation: Na2CO3 + 2HNO3 ==> 2NaNO3 + CO2 + H2O Next calculate moles of Na2CO3 used: 7.5 g x 1 mole/106 g = 0.071 moles Na2CO3 Then look at mole ratio of Na2CO3 to CO2 and see that it is 1 to 1 Thus, moles CO2 produced = 0.071 moles Finally, convert moles CO2 to grams of CO2: 0.071 moles x 44g/mole = 3.1 g (to 2 significant figures)
The reaction of carbon dioxide and potassium oxide is 4KO2 + 2CO2 = 2K2CO3 + 3O2. 156 grams of CO2 is 3.54 moles, which will produce 5.31 moles of O2.
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