answersLogoWhite

0

  • Chemistry
  • Weight and Mass
  • Elements and Compounds

How many moles of Cl2 are in 50.0 grams of Cl2?

User Avatar

Wiki User

βˆ™ 2009-02-14 08:40:31

Best Answer
Copy

# of Moles = Mass in grams divided by Molar Mass =5o divided by (cl x 2) =50 divided by 71 =0.704 moles

use:

1 mol = Mr in grams

that is 35.5x2 g of Cl2 = 1 mol

71g of Cl2 = 1 mol

therefore 50g of Cl2 = (1/71) x 50

=0.704 mol

2009-02-14 08:40:31
This answer is:
πŸ€“
🀯
πŸ€”
User Avatar

Your Answer

Loading...

Related Questions

79.3 grams of Cl2 to moles?

79.3 grams Cl2 (1mol/70.9 grams ) = 1.12 moles


How many grams cl2 needed to produce 1.5 moles of chloroform?

319g Cl2 are needed.


How many moles of PCl5 can be produced from 56.0g Cl2 and excess P4?

Balanced equation. 2P + 5Cl2 -> 2PCl5 56.0 grams Cl2 (1 mole Cl2/70.9 grams)(2 mole PCl5/5 moles Cl2) = 0.316 moles PCl5 produced


Which best represents the number of moles in exactly 84 grams of chlorine (Cl2) gas?

The number of moles in exactly 84 grams of chlorine (Cl2) gas 2,37.


How many grams are in NaCl with 2.34 moles of Cl2?

The mass of NaCl is 280 g.


How many grams Cl2 are needed to produce 1.5 moles CHCl3?

First realize that it takes 3 CL2 to produce one mole of CHCl3. So take 1.50 moles of CHCl3 * 3 moles of Cl2 / 1 mole of CHCL3= 4.5 mole of Cl2 The the atomic weight of Cl2 is 35.5*2=71g. 4.5 mole of Cl2*71g= 319.5g. of Cl2 needed.


How many moles of PCl5 can be produced from 25.0 grams of P4 and excess Cl2?

.807 mol


How many moles of PCl5 can be produced from 51.0 grams of Cl2 and excess P4?

0.288 mole


How many moles in 79.3g CL2?

The gram molecular mass of Cl2 is 70.906, twice the atomic mass of chlorine atoms. Therefore, 79.3 grams of Cl2 contains 79.3/70.906 or 1.12 moles, to the justified number of significant digits.


How many moles of PCl5 can be produced from 51.0g of Cl2 and excess P4?

The molar mass of Cl2 is 5.1 g/mol. If there is 51.0 g of Cl2 then there are 10 moles. 10 moles of Cl2 can produce 4 moles of PCl5.


How many grams is 64 moles of Cl?

64 moles of chlorine atoms would be 64 x 35.5 grams, i.e. 2272 grams. If you meant the substance chlorine, which consists of Cl2 molecules, it would be 4544 grams.


How many moles are in 1 g of Cl2?

12


What is volume occupied by 30lb of Cl2 at 743 mm Hg and 70 degree F?

Some conversion required.30 pounds Cl2 (454 grams/1 pound) = 13620 grams Cl213620 grams Cl2 (1 mole Cl2/70.9 grams) = 192.1 moles Cl270o F = 21.1o C = 294.3 Kelvinuse,PV = nRT(743 mm Hg)(X Volume) = (192.1 moles Cl2)(62.36 L*torr/mol*K)(294.3 K)Volume = 3525524.47/743= 4.7 X 103 Liters of chlorine gas------------------------------------------


How many moles are in 5.60 L Cl2 at STP?

17.7


How many moles of chlorine gas are contained in 9.02 x 1023 atoms?

9.02 X 10^23 atoms Cl2 (1mol Cl2/6.022 X 10^23) = 1.50 moles Cl2


How many moles of HCl gas are produced if 5.00 liters of Cl2 and excess H2 are reacted at STP?

Balanced equation first. Cl2 + H2 >> 2HCl Now use PV = nRT to find moles Cl2 as this limits and drives reaction. (1 atm)(5.00 L) = n(0.08206 Latm/molK)(298.15 K) = 0.204 moles Cl2 ( now use stoichiometry ) 0.204 moles Cl2 (2mole HCl/1 mole Cl2) = 0.408 moles HCl produced


How many moles of Cl are in one mole of FeCl2?

1 mole of Cl2. Assuming Fe + Cl2 -> FeCl2


How many moles of PCl5 can be produced from 30.0g of P4 and excess Cl2?

To find out how many moles of PCl5 can be formed from the reaction of P4 and Cl2, it is necessary to set up the stoichiometric equation. X P4 + Y Cl2 --> Z PCl5. Balancing the equation, X = 1, Y = 10, and Z = 4. This means that for every mole of P4 that reacts, 4 moles of PCl5 is produced. The next step is to find out how many moles of P4 are present in 30.0 grams. The molar mass of P4 is 123.895 g/mol, so there are .24214 moles of P4 present. Multiplied by 4, the answer is 0.96856 moles of PCl5 are produced.


In a reaction between sodium and chlorine 10 grams of sodium is needed to prepare 35 grams of sodium chloride How many grams of chlorine is needed for this reaction?

Balanced equation first. 2Na + Cl2 -> 2NaCl 35 grams NaCl (1 mole NaCl/58.44 grams )( 1 mole Cl2/2 mole NaCl )( 70.9 grams Cl2/1 mole Cl2) = 21 grams of Cl2 needed


Balance the following reaction Na plus Cl2 -- NaCl 2 and calculate the moles of Cl2 that can react with 5 mol Na and show your work?

2Na + Cl2 >> 2NaCl 5 moles Na (1mol Cl2/2 mole Na) = 2.5 moles Cl2 needed for this reaction.


When 4 moles of aluminum are allowed to react with an excess of chlorine gas CL2 how many moles of aluminum chlorde are produced?

4 moles


When 4 moles of aluminum are allowed to react with an excess of chlorine gas Cl2 how many moles of aluminum chloride are produced?

4 moles


What reactant is limiting if 3000 cm3 of Cl2 at STP react with a solution containing 25 grams of NaBr?

Cl2 + 2NaBr => Br2 + 2NaCl One mole Cl2 reacts with 2 moles NaBr Cl2 = 71 NaBr = 102.9 Molar volume = 22.414 L/mole for ideal gas @STP 3L Cl2 = 3/22.414 = 0.1338 mole 25g NaBr = 25/102.9 = 0.2430 mole 0.1338 moles Cl2 requires 0.2676 moles NaBr for complete reaction The NaBr is the limiting reagent


How many moles of hydrogen gas are needed to react with 15.1g chloride gas to produce hydrogen chloride gas?

H2 +Cl2---------------->2HCl Since H2 and Cl2 react in 1:1 mole ratio the number of moles of H2 reacting is equal to the number of moles of Cl2 which is equal to 0.213


How many moles of PCl5 can be produced from 26.0g of P4 and excess Cl2?

0.839