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What mass of will be produced from the given masses of both reactants?

28.0 g/P4 / 123.9 g/P4 = 0.2260 moles/ P4

0.2260 moles /P4 * 4 moles PCl5/1 mole/P4=0.904 moles/PCl5

54.0 g/Cl2 / 70.9 g/Cl2 = .7616 moles/Cl2

.7616 moles / Cl2 *4 moles PCl5/10 moles Cl2=.30

This is about limiting reagents

You need to use

2P + 5Cl2 --> 2PCl5

[or P4 + 10Cl2 --> 4PCl5 if you prefer]

that tells you that 2P = 62g needs 5Cl2 = 355g Cl2 to react

69.3g

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