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What mass of PCl 5 will be produced from the given masses of both reactants?
Wiki User
∙ 11y ago
What mass of will be produced from the given masses of both reactants?
28.0 g/P4 / 123.9 g/P4 = 0.2260 moles/ P4
0.2260 moles /P4 * 4 moles PCl5/1 mole/P4=0.904 moles/PCl5
54.0 g/Cl2 / 70.9 g/Cl2 = .7616 moles/Cl2
.7616 moles / Cl2 *4 moles PCl5/10 moles Cl2=.30
This is about limiting reagents
You need to use
2P + 5Cl2 --> 2PCl5
[or P4 + 10Cl2 --> 4PCl5 if you prefer]
that tells you that 2P = 62g needs 5Cl2 = 355g Cl2 to react
69.3g
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∙ 11y ago
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What mass of PCl5 will be produced from the given masses of both reactants which is 839 moles of P4 and 316 moles of Cl2 Answer needs to be submitted in grams though please?
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