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How many moles of HCl are required to completely react with .005 moles of NaOH?
Wiki User
∙ 8y ago
Verified answer
Simple equality.
(X L)(2.5 M HCl) = (1.5 L)(5.0 M NaOH)
2.5X = 7.5
X = 3.0 Liters needed
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Wiki User
∙ 12y ago
Wiki User
∙ 12y agoThis sounds like a typical neutralization reaction, so finding the moles of NAOH ( really OH-, but all one to one ) should suffice.
Molarity = moles of solute/liters of solution
or, for our purposes
moles of solute = liters of solution * Molarity
moles of NaOH = 1 liter * 5 M
= 5 moles NaOH
and if reaction is one to one
5 moles of H+ needed for complete neutralization
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Wiki User
∙ 15y agoWell, I'd have thought it would just be 5 moles, wouldn't it?
5HCl + 5NaOH > 5NaCl + 5H2O
or
HCl + NaOH > NaCl + H2O
Wiki User
∙ 8y agoIf you are looking for the reaction to go to completion, then 0.005mol of HCl are required, because the reaction happens in a 1:1 stoichiometric ratio: HCl + NaOH --> NaCl + H2O.
Wiki User
∙ 8y agoThis neutralization reaction is:
HCl + NaOH = NaCl + H2O
For 0,005 moles of sodium hydroxide the necessary amount of hydrogen chloride is also 0,005 moles.
Anonymous
30
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How many milliliters of 0.400 M NaOH are required to completely neutralize 20.00 mL of 0.200 M HCl?
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50ml HCl is titrated with a solution of 0.24m NaOH?
To calculate the number of moles of NaOH required to neutralize 50 mL of HCl, first convert 50 mL to liters. Next, use the molarity of NaOH (0.24 M) to determine the moles of NaOH required. Since HCl and NaOH react in a 1:1 ratio, the moles of NaOH will be equal to the moles of HCl.
How many grams of sodium hydroxide will react with 73.00 g of aqueous HCl?
The balanced chemical equation for the reaction between sodium hydroxide (NaOH) and hydrochloric acid (HCl) is 1 mol NaOH : 1 mol HCl. Calculate the amount of NaOH required by converting the given mass of HCl to moles using its molar mass, then use the mole ratio from the balanced equation to determine the moles of NaOH needed, and finally convert moles of NaOH to grams using its molar mass.
What volume in mL of a 1.06 M NaOH solution is required to neutralize 11 g of HCl?
First, calculate the number of moles of HCl using the molar mass. Then, determine the number of moles of NaOH needed to neutralize the HCl based on the 1:1 stoichiometry of the reaction. Finally, use the molarity of NaOH to find the volume required using the formula Molarity = moles/volume.
How much 1.00 M NaOH is required to react completely with 50.0 ml of 0.5 M CuIISO4?
The answer is 50 mL.
How many moles of MgOH2 will be produced when 30g of NaOH react with MgSO4?
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You need 4 moles of NaOH to prepare 2 liters of a 2.0 M solution. This is calculated by multiplying the volume (2 L) by the molarity (2.0 mol/L). The result gives you the moles needed.
What mass of lead(II) nitrate is required to react with 370-g NaOH?
The mass of lead(II) nitrate required to react with 370 g NaOH is 1 531,9 g.
How many liters of naoh are in 1.3 moles of 3.42 m of naoh?
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
What is the mass of 3.42 moles of NaOH?
The molar mass of NaOH is 40 g/mol. Therefore, the mass of 3.42 moles of NaOH would be 40 g/mol x 3.42 mol = 136.8 grams.
What volume in mL of a 1.06 M NaOH solution is required to neutralize 11 g of HCl?
First, calculate the number of moles of HCl using the molar mass. Then, determine the number of moles of NaOH needed to neutralize the HCl based on the 1:1 stoichiometry of the reaction. Finally, use the molarity of NaOH to find the volume required using the formula Molarity = moles/volume.
How grams of NaOH is required to nuetralize 100 ml of 1 M H2SO4?
Since H2SO4 is a diprotic acid, it will require twice the amount of NaOH to neutralize it. Therefore, molarity of NaOH should also be 1 M. 1 mole of H2SO4 reacts with 2 moles of NaOH. Therefore, to neutralize 1 mole of H2SO4, 2 moles of NaOH are required. To neutralize 1 mole of H2SO4 in 100 ml (0.1 L) of 1 M solution, you will need 0.1 moles of NaOH.
How many mls of a 2.00m solution of nitric acid are neded to completely react with 15.0g of sodium hydroxide according to the chemical action of hno3 plus naoh nano3 plus h2o?
NaOH = 40 Mwt so 15/40 moles present. This requires 15/40 moles of HNO3 from the above equation. The HNO3 contains 2 moles in 1000 ml and so 1 mole in 500 ml and therefore 500 x 15/40 = 137.5 mls required
How many moles of water are needed to react with 2.5 moles of sodium?
Na + 2H2O -----> H2 + NaOH If you have 2.5 moles water you need 1.25 mol elemental sodium
What is the limiting reagent in a reaction?
The limiting reagent in a reaction is the reactant that runs out first. For example, if you are reacting 10 moles of HCl and 5 moles of NaOH, you will get 5 moles of H20, 5 moles of NaCl, and 5 moles of HCl, because the remaining HCl had nothing to react with. Therefore, the NaOH is the limiting reagent.
How many moles of HNO3 are needed to prepare 5.0 liters of 2.0m soultion of HNO3?
To find the moles of HNO3 needed, we can use the formula: moles = Molarity x Volume (in liters). Substituting the values given, moles = 2.0 mol/L x 5.0 L = 10 moles of HNO3 needed to prepare a 2.0M solution in a 5.0 liter volume.
