The definition of 0.175 m KF is that 1 kg of water contains 0.175 moles of KF. Thus, 347 g of water is equivalent to 0.347 kg, and to find moles of KF, you calculate as follows:
0.175 moles/Kg x 0.347 kg = 0.0607 moles of KF are present (3 significant figures).
The molar mass of anhydrous potassium fluoride is 58,0967 g.
A 0,175 M solution has 10,167 g KF for 1 L.
So 347 g solution contain 3,528 g KF.
0.0175 in a percentage = 1.75%
19,5 g butane are needed.
Yes - that's what the standard definition is for 175.
Unfortunatly there isn't. But the Comet is the fastest car in the game. Here's the cheat - 227-555-0175
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