Moles KOH = Molarity x Volume = 0.214 moles/liter x 0.0602 liters = 0.0129 moles KOH. Remember, 60.2 mL = 0.062L
2 molar is 2mol per litre, i.e. 2/1000x60 moles. = 0.12 moles. which equals 6.7323g
This depends on the concentration of the solution.
You prepare a solution by dissolving a known mass of solute into a specific amount of solvent. In solutions, M is the molarity, or moles of solute per liter of solution. For 300 ml of a 0.1 M Na CL solution from a solid Na CL solution and water you need water and sodium chloride.
newtest3
You need to know the volume of liquid that contains the solid to answer this question. If you have one liter of a solution that contains 0.1 grams per milliliter, you can find the number of grams in the container through this calculation: 1 liter X 1000 ml/liter X 0.1 grams/ml = 100 grams of solid in the one liter of solution (the units for liters cancel out)
is a quarter a solid solution
Lithium fluoride has a solubility in water of 0.27 grams per 100 milliliters at 18 degrees Celsius. Its solubility drops to 0.134 grams at 25 degrees Celsius.Ê
See the two Related Questions to the left for the answer.The first is how to prepare a solution starting with a solid substance (and dissolving it). The second question is how to prepare a solution by diluting another solution.
Molarity = moles of solute/Liters of solution ( 220.0 ml = 0.220 Liters ) 0.500 M KOH = moles KOH/0.220 Liters = 0.110 moles KOH (56.108 grams/1 mole KOH) = 6.17 grams solid KOH needed
A solution of ammonia can be used to prepare ammoniumsulfate by reacting it with a solution of sulfuric acid to produce a solution of ammonium sulfate, which can be dried if desired to prepare solid ammonium sulfate.
32.4
You prepare a solution by dissolving a known mass of solute into a specific amount of solvent. In solutions, M is the molarity, or moles of solute per liter of solution. For 300 ml of a 0.1 M Na CL solution from a solid Na CL solution and water you need water and sodium chloride.
Pour a solution of Sodium(or Potassium) Iodide over Lead nitrate solution. The Lead iodide will be precipitated out as a yellow solid
So you want 0.04M but you have 400ml, not a litre. 0.04/1000*400 is 0.016 moles wanted. 0.016*40 (molecular weight) is 0.64g
0.0296 m Cr
newtest3
No. A solid-solid solution is called an alloy.
This is called an alloy (homogeneous solid-solid solution)
It isn't, what is important is getting the mixture to a tempurature where the precipitate is solid, and everything else is a liquid or in solution.