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How many grams of solid KOH is necessary to prepare 220.0 ml of 0.500 M KOH solution?
Wiki User
∙ 13y ago
Molarity = moles of solute/Liters of solution
( 220.0 ml = 0.220 Liters )
0.500 M KOH = moles KOH/0.220 Liters
= 0.110 moles KOH (56.108 grams/1 mole KOH)
= 6.17 grams solid KOH needed
Wiki User
∙ 13y ago
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