Pour a solution of Sodium(or Potassium) Iodide over Lead nitrate solution. The Lead iodide will be precipitated out as a yellow solid
Lead(II) iodide and Sodium nitrate
It produces Potassium nitrate and Lead iodide
A precipitate of Lead iodide and Potassium nitrate are formed
A precipitate of yellow Lead iodide and Sodium nitrate are formed
Lead(II) nitrate and potassium iodide are solids.
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
Lead(II) iodide and Sodium nitrate
It produces Potassium nitrate and Lead iodide
A precipitate of Lead iodide and Potassium nitrate are formed
Produces yellow Lead(II) iodide and Sodium nitrate
A precipitate of yellow Lead iodide and Sodium nitrate are formed
Aqueous lead nitrate plus aqueous sodium iodide produce solid lead iodide and aqueous sodium nitrate.
2KI+Pb(NO(3))(2) yields 2KNO(3)+PbI(2). You basically get potassium nitrate and lead (II) iodide when you react potassium iodide and lead nitrate dissolved in solution.
Lead(II) nitrate and potassium iodide are solids.
A yellow Lead(II) iodide precipitate
Na2
This is a double displacement reaction. 2KI + Pb(NO3)2 --> 2KNO3 + PbI2 Potassium iodide + Lead(II) nitrate --> Potassium nitrate + Lead(II) iodide A bright yellow precipitate will form when these two react.