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Q: How many moles of Lithium carbonate are needed to make a concentration of 12.7M in a 5 L solution Answer?
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What temperature is needed to decompose lithium carbonate?

At 1,300 degrees Celsius, lithium carbonate decomposes into lithium oxide and carbon dioxide gas. The equation for this decomposition is: Li2CO3 --> Li2O + CO2


How many grams of ammonium carbonate would you need to make 2.10 liters of a 0.619 M solution?

124,9 g grams of ammonium carbonate are needed.


What is the amount of solute needed to form a saturated solution?

it is solubility


What ratio of hydrated lime copper sulphate is needed to make 15 liters of solution?

Depending on the desired concentration of the solution !


How many grams of ammonium sulfate are needed to make a 0.25M solution at a concentration of 6M?

5.50


How much Magnesium Carbonate is needed to buffer a solution of twenty litres with pH 2.75 consisting of Cl in water to a pH of 5.4?

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You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml?

Image result for You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml? The concentration would be 0.76 mol/L.


How many grams of ammonium sulfate are needed to make a .25 M solution at a concentration of 6M?

1.5 moles


How onces of chemical per 384 oz of water?

It depends on the concentration of the solution. More info is needed to answer this question.


How much solute is needed to prepare 150mL of a 40.0 percent lithium nitrate solution?

150 mL x 40.0 g LiNO3/100 mL solution = 60.g of solute


How many moles of HNO3 are needed to prepare 5.0 liters of 2.0m soultion of HNO3?

Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.


What effect does the concentration of baking soda solution have on the amount needed to neutralizing an acid?

If it has a greater concentration, it will be considered more basic or alkaline. So, with a higher concentration, you will not need as much baking soda in your neutralization reaction.