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Sorry, I mean a HCl solution in water, not Cl.
It depends on the concentration of the solution. More info is needed to answer this question.
Answer=408.47 250Li2SO4/109.89Li2SO4/2x4x89.774 4LiNO3
A concentration of 110 M or 106 M doesn't exist.
51.2 g H20
At 1,300 degrees Celsius, lithium carbonate decomposes into lithium oxide and carbon dioxide gas. The equation for this decomposition is: Li2CO3 --> Li2O + CO2
124,9 g grams of ammonium carbonate are needed.
it is solubility
Depending on the desired concentration of the solution !
5.50
Sorry, I mean a HCl solution in water, not Cl.
Image result for You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml? The concentration would be 0.76 mol/L.
1.5 moles
It depends on the concentration of the solution. More info is needed to answer this question.
150 mL x 40.0 g LiNO3/100 mL solution = 60.g of solute
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
If it has a greater concentration, it will be considered more basic or alkaline. So, with a higher concentration, you will not need as much baking soda in your neutralization reaction.