First, balance the equation to get your proper molar ratios:
N2 + 3H2 --> 2NH3
Now, plug in 7.5 moles of H2 instead of the coefficient of 3. A direct proportion may help:
3/2=7.5/x, solve for x to get 5 moles of NH3.
The equation for the reaction of nitrogen and hydrogen to form ammonia is N2 + 3 H2 -> 2 NH3. This equation shows that each mole of ammonia requires 3/2 mole of H2. The gram molecular mass of H2 is 2.016. Therefore, 7.5 gm of hydrogen corresponds to 7.5/2.016 or 3.7 moles, to the justified number of significant digits. This will make 3.7(2/3) or 2.47 moles of ammonia. The last digit of the answer is depressed because it may not be accurate to + 1. (The datum 7.5 is given only to two significant digits.)
Steps to get the right answer
1. Look at the equation
2. The question is asking for how many moles of N2 reacted!
3. So that means you should look to start with 0.75moleNH3
4. You would want the NH3 to cancel so you look back at the equation and find that 2 is in front of NH3 to balance the equation.
5. What you should have now:
[0.75mole NH3/2molesNH3]
6.Then you look back at the question again and find that it wants N2 *reminder!
7. So then look back at the equation and find that there is a 1 in front of N2.
8. After you cancel out the NH3 you dividing 0.75 and 2(NH3 Cancels)
9. Then you should be left with the answer 0.375 mol N2
Enough nitrogen means equal or in excess, so.....
3H2 + N2 -> 2NH3
7.5 mole hydrogen gas (2 mole NH3/3 moles H2)
= 5.0 mole ammonia made
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Write the balanced equation: N2 + 3H2 ==> 2NH3 7.9 moles N2 x 2 moles NH3/1 mole N2 = 15.8 moles NH3 formed (assuming H2 isn't limiting).
Corrected for 2 significant figures, answer would be 16 moles
Molecular mass of NH3 is 17.So there are 4.5588mol.
3.81 mol
9
The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
3H2 + N2 <------> 2NH3 is the balanced equation for Hydrogen and Nitrogen making ammonia. 3 moles of H2 produces two moles of ammonia and thus to make 6 moles requires 9 moles of Hydrogen.
The chemical equation is N2 + 3H2 -> 2NH3 So reacting 2 moles of N2 will produce 4 moles ammonia.
N2 + 3H2 --> 2NH3 You have been told, indirectly, that nitrogen limits and will drive the reaction. 3 moles N2 (2 moles NH3/1 mole N2) = 6 moles ammonia gas produced ========================
The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2
That amount of ammonia contains two moles of hydrogen gas. One mole of hydrogen gas weighs 2.016 grams. Therfore 3.75 grams of ammonia contains two moles of hydrogen.
To form ammonia, reaction is N(2) + 3H(2) ---> 2NH(3) + H(2)O. As you can see for 1 mole of nitrogen three moles of hydrogen is required. Hence for your question, 1.13 moles nitrogen is required.
First you have to find the limiting reactant. You have .3 moles of nitrogen and .6 moles of hydrogen, but you don't know which one is going to run out first.In any of these stoichiometry problems, you need to write down the formula:N2 + 3H2 → 2NH3Take both nitrogen and hydrogen and figure out how much ammonia is made alone..6 moles Hydrogen ÷ 3 moles hydrogen × 2 moles ammonia = .4 moles ammonia made.3 moles Nitrogen ÷ 1 mole nitrogen × 2 mole ammonia = .6 moles ammonia madeNow you figured out that hydrogen is the limiting reactant and the nitrogen is the excess because less ammonia is made using hydrogen. This measurement is what you will be using for the rest of the problem.Take the limiting reactant and use stoichiometry to find how much ammonia can be made.You could start with .6 moles of hydrogen and do the same conversion as above, but add the step of converting to grams. Or, since you already found out that .4 moles ammonia is made, just convert it to grams. The molecular mass of ammonia is 17.0 grams..4 moles ammonia × 17.0 grams = 6.8 grams ammonia
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
To form ammonia, balanced reaction is N(2) + 3H(2) ---> 2NH(3) + H(2)O. As you can see for 1 mole of nitrogen three moles of hydrogen is required. Hence for your question, 3 moles nitrogen is required to satisfy the ratio.
3H2 + N2 <------> 2NH3 is the balanced equation for Hydrogen and Nitrogen making ammonia. 3 moles of H2 produces two moles of ammonia and thus to make 6 moles requires 9 moles of Hydrogen.
8,038 moles of ammonia were produced.
9H2 + 3N2 ------> 6NH3 3 moles of N2 would be required.
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
N2 + 3H2 -> 2NH3 3 moles hydrogen gas. You should know that because of the formula of ammonia.
The chemical equation is N2 + 3H2 -> 2NH3 So reacting 2 moles of N2 will produce 4 moles ammonia.