8 mol
6 moles
The reaction is:WO3 + 3 H2 = W + 3 H2OThree moles of hydrogen for one mole of wolfram.
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
0,044 moles of NH3 can be produced.
6 moles
X = 0.489 moles of AgCl produced
30 moles
4 moles
4 moles
The answer is 30 moles.
30 moles
None, unless there is metallic potassium in the reaction mixture. Assuming excess potassium metal is present then 14 moles of KBr can be produced. 7BaBr2 + excess potassium -----> 14KBr + 7 Ba
11,2 moles carbon dioxide are obtained.
Equation. 2Al + 3Cl2 -> 2AlCl3 one to one again 0.440 moles Al (2 moles AlCl3/2 moles Al) = 0.440 moles AlCl3 produced
The reaction is:WO3 + 3 H2 = W + 3 H2OThree moles of hydrogen for one mole of wolfram.
If burnt with excess O2 then 19.65 (=3*6.55) mole H2O