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How many moles of NaN3 would have to decompose in order to generate 253 million molecules of nitrogen?
Wiki User
∙ 11y ago
There is no such substance as NaN3. There is, however, Na3N, which is the ionic compound sodium nitride. Decomposing this compound would probably take a considerable amount of energy, but provided you could do it, the correctly balanced formula would be 2Na3N-->6Na+N2. One mole of anything contains 6.02x1023 representative particles. 253 million is 2.53x108. That amounts to 4.20x10-16 moles (a tiny amount!) The mole ratio of nitrogen product to sodium nitride reactant is 1 to 2, so double that amount to get 8.40x10-16. Still a tiny amount, but it's the answer. This is a good problem to illustrate just how small a sample of something can still contain many millions of particles.
Wiki User
∙ 11y ago
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