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That amount of ammonia contains two moles of hydrogen gas. One mole of hydrogen gas weighs 2.016 grams. Therfore 3.75 grams of ammonia contains two moles of hydrogen.

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10y ago
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14y ago

Pure methane cannot contain ammonia molecules. These are two different compounds

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12y ago

well if thats 75.0g there would be 37.13 moles

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10y ago

2NH3 ----> 3H2 + N2 so 2 moles of ammonia produce 1 of Nitrogen. So to produce 3.5 moles of nitrogen would require 2 x3.5 = 7 moles.

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Q: How many moles of ammonia are needed to produce 3.5 mole of nitrogen?
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How many moles of nitrogen and hydrogen are needed to get 10 moles of ammonia?

The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2


How many moles of ammonia are produced from the reaction of 90.0 L of nitrogen?

8,038 moles of ammonia were produced.


How many moles of ammonia are produced from 12.0 moles of hydrogen?

N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.


How many moles of hydgrogen are needed to produce 6.0 moles of ammonia?

This is based on calculations too. It contains 18 hydrogen moles.


In order to get 1 mole of ammonia how many moles of nitrogen is needed?

Each mole of ammonia requires one mole of nitrogen atoms. However, the nitrogen in the air occurs as diatomic molecules; therefore, only one-half mole of molecular nitrogen is required for each mole of ammonia.


What mass of nitrogen is needed to make 34 g of ammonia?

1 mole of nitrogen makes 3 of ammania so.. moles of ammonia=34/17=2 moles as 1 mole of nitrogen makes 3 of ammania so.. 2/3 x 2 x14 = 18.67 g


How many molecules of ammonia can be formed from the reaction of 2 molecules of Nitrogen gas and 6 molecules of hydrogen gas?

The chemical equation is N2 + 3H2 -> 2NH3 So reacting 2 moles of N2 will produce 4 moles ammonia.


How many moles of nitrogen are needed to convert 9.0 mole hydrogen gas to ammonia gas?

To form ammonia, balanced reaction is N(2) + 3H(2) ---> 2NH(3) + H(2)O. As you can see for 1 mole of nitrogen three moles of hydrogen is required. Hence for your question, 3 moles nitrogen is required to satisfy the ratio.


How many elements are in a ammonia?

There are two elements that make up Ammonia (NH3) … One mole of Nitrogen (N) plus three moles of Hydrogen (H) react to produce one mole of Ammonia (NH3)


How many moles of nitrogen dioxide are needed to react with 5.0 moles of water?

10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.


How many liters of n2 gas at stp will be used to produce 8.16 liters of nh3 gas at stp are consumed?

Assuming that you mean the reaction of nitrogen and hydrogen to form ammonia N2 + 3H2 -> 2NH3 1 mole of nitrogen forms 2 moles of ammonia- so 4.08 l of nitrogen will be consumed to form 8.16 moles of ammonia. This assumes both are pretty ideal gases which is a reasonabale approximation.


How many moles of hydrogen are required to produce 18.00 moles of ammonia?

N2 + 3H2 -> 2NH3 The stoichiometric equation (or balanced equation) for the formation of ammonia from this we can read off the mole ratio between hydrogen and ammonia; 3M H2 needed to produce 2M NH3 times each by 9 (so the ratio remains the same and 18M NH3 is formed) 27M H2 needed to produce 18M NH3