Approx 1.2487 moles.
moles = mass in grams / atomic weight So moles in 37.9 g or argon = 37.9 / 39.948 = 0.948 moles
Approx 0.223 moles.
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles
Have: 607gAr Need: Moles of Argon From the periodic table we know that there are 39.948gAr per every 1 mole of Argon. 607g/39.948 = your answer.
0.25 moles, approx.
moles = mass in grams / atomic weight So moles in 37.9 g or argon = 37.9 / 39.948 = 0.948 moles
Approx 0.223 moles.
1,67.1024 argon atoms is equal to 2,773 moles.
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles
Have: 607gAr Need: Moles of Argon From the periodic table we know that there are 39.948gAr per every 1 mole of Argon. 607g/39.948 = your answer.
0.25 moles, approx.
1.7x10^-18
55.64
A mole of argon includes Avogadro's Number of atoms of argon. Therefore, the answer is (3.0 X 1024)/(6.022 X 1023) or 5.0 moles, to the justified number of significant digits.
Moles = mass in grams / atomic weight So moles in 15.01 g of Ar = 15.01 / 39.948 = 0.38 moles
51.736 moles
1,638 moles contain 9,864266723766.10e23 atoms.