Add the atomic weights of one C atom and two O atoms.
That's the number of grams in one mole.
Use division to find the number of moles in your 211 g.
To determine the number of moles in 211 g of carbon dioxide, we need to divide the given mass by the molar mass of carbon dioxide. The molar mass of carbon dioxide (CO2) is approximately 44 g/mol. Divide 211 g by 44 g/mol to find that there are approximately 4.80 moles of carbon dioxide in 211 g.
To find the number of moles of MgS2O3 in 211 g of the compound, you need to first calculate the molar mass of MgS2O3. This is 120.37 g/mol. Then, divide the given mass by the molar mass to get the number of moles. In this case, 211 g / 120.37 g/mol = 1.75 moles of MgS2O3.
Two: 1 and 211.
The molar mass of P4 is 123.9 g/mol, and the molar mass of P2O5 is 141.94 g/mol. The stoichiometry of the reaction shows that 1 mol of P4 produces 1 mol of P2O5. Therefore, the maximum amount of P2O5 that can be produced from 211 g of P4 is 211 g / 123.9 g/mol = 1.70 mol of P2O5.
211 fluid ounces is 1.648 gallons.
211
211 centimeters is equal to 2.11 meters.
Answer: 211 ft² = 19.6025 m²
211 square meters is 22.7 squares.
You need to get the Moles of CO2 first. 9.3 g. CO2/44 g CO2= .211 mol Then just put it into the ideal gas law at STP. PV=nRT 1.0 ATM x P = (.211 mol) (.08206) (273.15 k)---->"Plug and Chug" P = (.211 mol) (.08206) (273.15 k) / 1.0 ATM P= 4.7 L ---> 4,700 mL
There are 100 centimetres in one metre. Therefore, 211 centimetres is equal to 211/100 = 2.11 metres.
211 US fluid ounces = 1.6484375 US gallons