How many moles of carbon dioxide are produced when 10 moles of propane are combusted?

Answer 1

This question sound like one that can easily be answered if one has a general chemistry textbook. My advice is to look at doing some unit conversions to find out how many moles of propane are in 36.1 g of propane first. With a balanced chemical equation for combustion, and assuming the propane is the limiting reagent, use dimensional analysis to convert your moles of propane to moles of carbon dioxide.

Answer 2

The reaction for the complete combustion of propane is:

C3H8 + 5O2 --> 3CO2 + 4H2O

So for every mole of propane combusted 3 moles of carbon dioxide are formed. Therefore combusting 10 moles of propane will form 30 moles of carbon dioxide.

Answer 3

C3H8 + 5O2 -> 3CO2 + 4H2O

30 moles propane gas (3 mole CO2/1 mole C3H8)(1 mole C/1` mole CO2)

= 90 moles of carbon produced

-----------------------------------------( could have been different id carbon and carbon dioxide were not one to one as an internal molecule )

Answer 4

The complete combustion of propane occurs according to the following balanced equation: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. This equation shows that three moles of carbon dioxide are produced for each mole of propane burned. Therefore, burning 7.5 moles of propane will produce 22.5 moles of carbon dioxide. The gram molecular mass of carbon dioxide is 44.01; therefore, 22.5 moles has a mass of 22.5 x 44.01 or 9.9 X 102 grams, to the justified number of significant digits.

Answer 5

This is a chemical calculation. 57.9 MOLES of CO2 will formed.