Fe ions =,
Fe 2+
and
Fe 3+
Oxygen ions =,
O 2-
So, as you should see, Fe3O4, is an invalid species as the charge on the first iron ion would be 3 * 2+ = 6 +, and the charge on the second iron ion would be 3 * 3+ = 9+. This can not equal 4 * 2- = 8 -.
Balanced equation.
4Fe + 3O2 -> 2Fe2O3
6.25 moles O2 (4 moles Fe/3 moles O2)
= 8.33 moles Fe needed
Balanced equation.
2Fe + 3O2 -> 2FeO3
6 moles FeO3 (3 moles O2/2 moles FeO3)
= 9 moles oxygen
-----------------------
The answer is 2 moles.
The answer is 10 moles of carbon monoxide.2 C + O2 = 2 CO
3 moles of O, so that must be 6 moles of O2
The answer is 0,173 moles.
4.80 grams O2 (1 mole O2/32 grams ) = 0.150 moles of O2
To determine the number of moles of Fe that can be made from 25 moles of Fe2O3, you need to write the balanced chemical equation for producing O2 from Fe2O3. 2Fe2O3 = 4Fe + 3O2, which means that 2 moles of Fe2O3 will produce 4 moles of Fe and 3 moles of O2 . Set up a proportion. 3 moles of O2 ÷ 2 moles of Fe2O3 = x moles of O2 ÷ 25 moles of Fe2O3 Cross multiply and divide. 3 moles of O2 * 25 moles of Fe2O3 ÷ 2 moles of Fe2O3 = 37.5 moles of O2 produced.
The answer is 2 moles.
Al + O2 will never yield Fe2O3.
150.0 g O2 x 1 mole O2/32 g O2 = 4.688 moles O2
Balanced equation. 2S + 3O2 --> 2SO3 1.32 moles O2 (2 moles SO3/3 moles O2) = 0.880 moles sulfur trioxide produced ========================
0.361 moles O2
4
15 moles O2 (32 grams/1 mole O2) = 480 grams
The answer is 10 moles of carbon monoxide.2 C + O2 = 2 CO
3 moles of O, so that must be 6 moles of O2
2Al + 3O2 --> 2Al2O3 0.78 moles O2 (2 moles Al2O3/3 moles O2) 0.52 moles Al2O3 produced ===========================( assuming oxygen limits )
what is ag2o