The answer to the conversion is that 35.0 grams of hydrochloride (HCL) equals 0.76 moles. The conversion rate is 35.0 grams divided by 46 gram per mole. A mole is the molecular weight of a substance.
molar mass of NaHCO3 =84
moles of nahco3 =0.35/84 = 4.2*10^-3 moles
with balanced equation{ HCl + NaHCO3 ---> NaCl + H2O + CO2}, one mole of HCl react with one mole of NaHCO3 but 4.2*10^-3 moles of NaHCO3 react with =4.2*10^-3*1 mol hcl=4* 10^-3 moles
Divide mass (g) by molar mass (g/mol) :
30 g C2H2 = 30/26 g
35 g H2O = 35/18 g
Na2CO3+2HCl-->2NaCl + CO2 ratio is 1:2.So 0.00265 x 2 mol of HCl needed.So 0.0053mol needed.
35,0 g HCl is equivalent to 0,96 moles.
35 g of NaCl is equal to 0.6 mol.
About 9.11 g.
0.960
How many moles of C are needed to react with 0.490 mole SO2?
6moles of hydrogen
1.28moles
The answer is 1,25 moles iron(III) oxide.
3.00 grams NaHCO3 (1 mole/84.008 grams) = 0.0357 moles of sodium bicarbonate
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
How many moles of C are needed to react with 0.490 mole SO2?
6moles of hydrogen
The answer is 699 moles perchloric acid.
These reagents doesn't react.
0.083
1.28moles
1.35
63 g of water are needed.
The same amount.
For this you need the atomic (molecular) mass of NaHCO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaHCO3=84.0 grams110 grams NaHCO3 / (84.0 grams) = 1.31 moles NaHCO3
The answer is 1,25 moles iron(III) oxide.