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How many moles of hydrogen are produced from the reaction of three moles of zinc with an excess of hydrochloric acid?
Wiki User
∙ 13y ago
I assume zinc limits in this reaction. Balanced equation.
Zn + 2HCl -> ZnCl2 + H2
184 grams Zn (1 mole Zn/65.41 grams)(1 mole ZnCl2/1 mole Zn)
= 2.81 moles zinc chloride produced
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Wiki User
∙ 12y ago
Wiki User
∙ 13y ago20 mol HCl gives 10 mol H2 weighting 10 (mol) * 2 (g/mol) = 20 g Hydrogen, but ONLY when there is (just) enough zinc (also 10 mol Zn = 10*65.4 = 654 g !!) to react!
Zn + 2 HCl --> H2 + ZnCl2
Wiki User
∙ 13y agoCorrection: The correct balanced equation is Zn + 2HCL = ZnCl2 + H2
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∙ 12y agomol of H2= 3mol Zn * 1mol H2/ 1mol Zn = 3mol H2
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∙ 13y ago1 mole of H2 gas is produced for every mole of magnesium and ever 2 moles of hydrochloric acid.
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∙ 12y ago3 mol Zn x 1H2 / 1 MOL zN = 3 MOL H2
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∙ 12y agododo birds
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∙ 12y agothree
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∙ 12y agosix
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How many molecules are produced when 2.5g of zinc react with an excess of hydrochloric acid?
molecules of what?
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