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How many moles of nitrogen would react with excess hydrogen to produce 520 mL of ammonia?
Wiki User
∙ 9y ago
The balanced equation is- N(2) + 3H(2) ---> 2NH(3).
There fore the ratio says that for one molecule of nitrogen, 2 molecules of ammonia is produced. Also Avogadros Law states that number of molecules of gas is directly proportional to volume occupied. Hence 260 mL of nitrogen is required.
However you have not told what are other physical conditions like pressure and temperature. So we cannot find the number of moles.
Wiki User
∙ 8y ago
Wiki User
∙ 8y agoIt cannot be counted directly. Pressures and temperature should be given
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Are hydrogen gas and ammonia gas explosive?
Hydrogen is explosiveAmmonia when mixed with oxygen, it burns with a pale yellowish-green flame.At high temperature and in the presence of a suitable catalyst, ammonia is decomposed into its constituent elements. Ignition occurs when chlorine is passed into ammonia, forming nitrogen and hydrogen chloride; if chlorine is present in excess, then the highly explosive nitrogen trichloride (NCl3) is formed.
How many grams of NH3 can be produced from 4.12mol of N2 and excess H?
The gram molecular mass of ammonia is 17.03. The formula shows that only one atom of nitrogen is required for each mole of ammonia; 4.12 mol of diatomic nitrogen contains 8.24 mol of nitrogen atoms, and with excess H, all of this nitrogen can be converted to ammonia. Therefore, 8.24 mol of ammonia can be produced, and multiplying this number by17.03 yields a total mass of 140.3 grams of ammonia, to the justified number of significant digits.
If .3 mole of N2 are reacted with .6 mole of H2 what mass of NH3 could form the formula N2 plus 3 H2 makes 2 NH3 The answer to the problem is 6.8 but don't know how to get that?
First you have to find the limiting reactant. You have .3 moles of nitrogen and .6 moles of hydrogen, but you don't know which one is going to run out first.In any of these stoichiometry problems, you need to write down the formula:N2 + 3H2 → 2NH3Take both nitrogen and hydrogen and figure out how much ammonia is made alone..6 moles Hydrogen ÷ 3 moles hydrogen × 2 moles ammonia = .4 moles ammonia made.3 moles Nitrogen ÷ 1 mole nitrogen × 2 mole ammonia = .6 moles ammonia madeNow you figured out that hydrogen is the limiting reactant and the nitrogen is the excess because less ammonia is made using hydrogen. This measurement is what you will be using for the rest of the problem.Take the limiting reactant and use stoichiometry to find how much ammonia can be made.You could start with .6 moles of hydrogen and do the same conversion as above, but add the step of converting to grams. Or, since you already found out that .4 moles ammonia is made, just convert it to grams. The molecular mass of ammonia is 17.0 grams..4 moles ammonia × 17.0 grams = 6.8 grams ammonia
Kjeldahl method for estimation of nitrogen in inorganic organic compound?
This is a very convenient method but its use is restricted.This method is suitable for estimating nitrogen in those organic compounds in which nitrogen is linked to carbon and hydrogen. The method is not used in the case of nitro, azo and azoxy compounds. The method is extensively used for estimated nitrogen in food, fertilizers and agricultural products.Principle:- the method is based on the fact that when the nitrogenous compound is heated with concentrated sulphuric acid in presence of copper sulphate, the nitrogen present in the compound is quantitatively converted to ammonium sulphate. The ammonium sulphate so formed is decomposed with excess of alkali and the ammonia evolved is estimated volumetrically. The percentage of nitrogen is then calculated from the amount of ammonia.
When 500g of ammonia reacted with excess sulfuric acid to produce ammonium sulfate 1789g of product were obtained What is the percent yield of ammonium sulfate for this reaction?
92.22%.
What do high temperature's high pressure combustion's nitrogen fixation's and lightning produce a excess carbon b excess nitrogen c nitrates d ammonia?
excess nitrogen
Are hydrogen gas and ammonia gas explosive?
Hydrogen is explosiveAmmonia when mixed with oxygen, it burns with a pale yellowish-green flame.At high temperature and in the presence of a suitable catalyst, ammonia is decomposed into its constituent elements. Ignition occurs when chlorine is passed into ammonia, forming nitrogen and hydrogen chloride; if chlorine is present in excess, then the highly explosive nitrogen trichloride (NCl3) is formed.
How many grams of NH3 can be produced from 4.12mol of N2 and excess H?
The gram molecular mass of ammonia is 17.03. The formula shows that only one atom of nitrogen is required for each mole of ammonia; 4.12 mol of diatomic nitrogen contains 8.24 mol of nitrogen atoms, and with excess H, all of this nitrogen can be converted to ammonia. Therefore, 8.24 mol of ammonia can be produced, and multiplying this number by17.03 yields a total mass of 140.3 grams of ammonia, to the justified number of significant digits.
If .3 mole of N2 are reacted with .6 mole of H2 what mass of NH3 could form the formula N2 plus 3 H2 makes 2 NH3 The answer to the problem is 6.8 but don't know how to get that?
First you have to find the limiting reactant. You have .3 moles of nitrogen and .6 moles of hydrogen, but you don't know which one is going to run out first.In any of these stoichiometry problems, you need to write down the formula:N2 + 3H2 → 2NH3Take both nitrogen and hydrogen and figure out how much ammonia is made alone..6 moles Hydrogen ÷ 3 moles hydrogen × 2 moles ammonia = .4 moles ammonia made.3 moles Nitrogen ÷ 1 mole nitrogen × 2 mole ammonia = .6 moles ammonia madeNow you figured out that hydrogen is the limiting reactant and the nitrogen is the excess because less ammonia is made using hydrogen. This measurement is what you will be using for the rest of the problem.Take the limiting reactant and use stoichiometry to find how much ammonia can be made.You could start with .6 moles of hydrogen and do the same conversion as above, but add the step of converting to grams. Or, since you already found out that .4 moles ammonia is made, just convert it to grams. The molecular mass of ammonia is 17.0 grams..4 moles ammonia × 17.0 grams = 6.8 grams ammonia
How many moles of ammonia gas are produced by the reaction of 3 mole of nitrogen gas with excess hydrogen gas N2 H2 ---- NH3?
N2 + 3H2 --> 2NH3 You have been told, indirectly, that nitrogen limits and will drive the reaction. 3 moles N2 (2 moles NH3/1 mole N2) = 6 moles ammonia gas produced ========================
If an excess of nitrogen is reacted with 3.41 grams of hydrogen how many grams of ammonia can be produced?
Balanced equation first. N2 + 3H2 >> 2NH3 (hydrogen is limiting and drives the reaction ) 3.41 grams H2 (1mol/2.016g )(2mol NH3/3mol H2 )(17.034g NH3/1mol NH3 ) = 19.2 grams of ammonia produced ( this is called the Born-Haber process )
N2(g)+3H2(g)=2NH3(g)If a sample of 4.50 moles of hydrogen gas was reacted with excess nitrogen how many moles of ammonia gas would be produced?
3.50 W 21.80 x 1/14th
How many moles of ammonia are produced when 6 mol of hydrogen gas react with an excess of nitrogen gas?
3H2 + N2 <------> 2NH3 is the balanced equation for Hydrogen and Nitrogen making ammonia. 3 moles of H2 produces two moles of ammonia and thus to make 6 moles requires 9 moles of Hydrogen.
What is the chemical equation liquid nitrogen reacts with an excess of hydrogen gas?
3 H2 + N2 = NH3
Kjeldahl method for estimation of nitrogen in inorganic organic compound?
This is a very convenient method but its use is restricted.This method is suitable for estimating nitrogen in those organic compounds in which nitrogen is linked to carbon and hydrogen. The method is not used in the case of nitro, azo and azoxy compounds. The method is extensively used for estimated nitrogen in food, fertilizers and agricultural products.Principle:- the method is based on the fact that when the nitrogenous compound is heated with concentrated sulphuric acid in presence of copper sulphate, the nitrogen present in the compound is quantitatively converted to ammonium sulphate. The ammonium sulphate so formed is decomposed with excess of alkali and the ammonia evolved is estimated volumetrically. The percentage of nitrogen is then calculated from the amount of ammonia.
What is the difference between ammonia and ammonium chloride?
Ammonia is NH3, or a nitrogen atom bonded to 3 hydrogen atoms. By replacing one, two, or all three of the hydrogens with ethanol ( CH3-CH2-OH ), with the CH3 end being the one that bonds to the nitrogen, you create an ethanolamine. If one hydrogen is replaced with ethanol, you get monoethanolamine (MEA); if two hydrogens are replaced, you get diethanolamine (DEA); if all three hydrogens are replaced, you get triethanolamine (TEA). MEA can be represented as NH2-(CH2-CH2-OH). DEA can be represented as NH-(CH2-CH2-OH)2. TEA can be represented as N-(CH2-CH2-OH)3.
300 g of ammonia react with 36 moles of sulfuric acid to produce ammonia sulfate how many moles of excess sulfuric acid are left over after the reaction is complete?
26.9 - 27.4
