2C2H2 + 5O2 ---->4CO2 + 2H2O so 1 mole of acetylene (ethyne) reacts with 2.5 moles of oxygen.
Answer 2.5 moles
The ratio of propane to oxygen is 1:5. So for every mole of propane, 5 moles of oxygen gas are required for the complete combustion of propane.Balanced equation:C3H8 + 5O2 --> 3CO2 + 4H2O
.44 moles BeCl2
Balanced equation: 2H2S + 302 = 2SO2 + 2H20
The answer is 0,8 moles oxygen.
Balanced equation first. 2CH4O + 3O2 -> 2CO2 + 4H2O 23.5 moles methanol (3 moles O2/2 mole CH4O) = 35.3 moles oxygen needed --------------------------------------
65
.913 moles
The ratio of propane to oxygen is 1:5. So for every mole of propane, 5 moles of oxygen gas are required for the complete combustion of propane.Balanced equation:C3H8 + 5O2 --> 3CO2 + 4H2O
.44 moles BeCl2
Balanced equation: 2H2S + 302 = 2SO2 + 2H20
The answer is 152 g oxygen.
The nunber of moles of oxygen is 2,5.
The answer is 3,375 moles oxygen.
4NH3 + 3O2 -----> 2N2 + 6H2O 4 moles of ammonia react with 3 of oxygen. So 10 moles of ammonia requires 7.5 moles of oxygen.
5g of oxygen are required to completely react with 10g of hydrogen resulting in water with no net losses. Or exactly 2:1 = H20 (2 hydrogen < > 1 oxygen)
The answer is 0,8 moles oxygen.
1,8 moles of oxygen are necessary.