Chemistry

# How many moles of oxygen will be needed to completely oxidize 64g CH4?

012 ###### 2016-10-27 12:28:20

7,98 moles of oxygen are needed to completely oxidize 64g CH4.

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## Related Questions The minimum number of moles of 02 that are needed to completely react with 16 moles of NH3 is 12 moles oxygen.              Oxygen (O2) and glucose (C6H12O6) react to form carbon dioxide (CO2) and water (H20) through an oxidation/reduction reaction. The reaction is C6H12O6 + 6O2 = 6C02 + 6H20. Therefore, for every 1-mole of glucose 6-moles of oxygen are needed. 25 moles of oxygen is enough to burn two moles of gasoline. How many moles of magnesium are needed to react with 16 g of molecular oxygen? 2 KClO3 ----&gt; 2KCl + 3O2 So 2 moles of Potassium Chlorate produces 3 moles of oxygen molecules or 6 moles of oxygen atoms. 3 moles of Potassium chlorate would thus produce 4.5 moles of oxygen molecules or 9 moles of oxygen atoms.  40 moles of oxygen atoms would be required, but because oxygen usually occurs as diatomic molecules, only 20 moles of molecular oxygen would be required. Balanced equation. 2Fe + 3O2 -&gt; 2FeO3 6 moles FeO3 (3 moles O2/2 moles FeO3) = 9 moles oxygen -----------------------  4NH3 + 3O2 -----&gt; 2N2 + 6H2O 4 moles of ammonia react with 3 of oxygen. So 10 moles of ammonia requires 7.5 moles of oxygen. I have already balanced - 2C2H2+5O2-&gt;4CO2+2H2O what do I do next? 2 moles acetylene--------------5 moles oxygen O2 7 moles acetylene--------------x moles oxygen O2 x = 7 x 5/2 = 17,5 This is a reaction that I do not remember the name of, but, no matter, balanced equation first. 2Mg + O2 &gt;&gt; 2MgO 10 moles Mg (1mol O2/2mol Mg) = 5 moles oxygen gas needed.

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