Molar mass:
Reaction:
Calculus
The balanced chemical equation for the reaction between hydrogen and oxygen is: 2H2 + O2 -> 2H2O This equation shows that 1 mole of O2 reacts with 2 moles of H2. So, to completely react with 6 moles of H2, you would need 3 moles of O2.
The balanced chemical equation for the reaction between oxygen (O2) and hydrogen sulfide (H2S) is: 2H2S + 3O2 -> 2SO2 + 2H2O From the equation, it is a 3:2 ratio of O2 to H2S. Therefore, if 2.3 moles of H2S are present, (2.3 moles H2S) * (3 moles O2 / 2 moles H2S) = 3.45 moles of O2 are needed.
For the reaction of propane (C3H8) with oxygen (O2), the balanced equation is: C3H8 + 5O2 -> 3CO2 + 4H2O. This means that 5 moles of O2 are required to react completely with 1 mole of propane (C3H8). Therefore, to react completely with 4 moles of propane, you would need 20 moles of O2.
The balanced equation shows that 2 moles of H2S react with 3 moles of O2. Therefore, to react completely with 2.3 moles of H2S, you would need (3/2) x 2.3 moles of O2 which is equal to 3.45 moles of O2.
4 moles of oxygen atoms are present in 4 moles of H2O
To determine how many moles of oxygen are needed to completely react with isooctane (C₈H₁₈), we can use the balanced combustion reaction: 2 C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O. From this equation, 2 moles of isooctane react with 25 moles of oxygen, indicating that 1 mole of isooctane requires 12.5 moles of oxygen. Therefore, for 4 moles of isooctane, 4 × 12.5 = 50 moles of oxygen are needed.
8,75 moles of oxygen are needed.
The balanced chemical equation for the reaction between hydrogen and oxygen is: 2H2 + O2 -> 2H2O This equation shows that 1 mole of O2 reacts with 2 moles of H2. So, to completely react with 6 moles of H2, you would need 3 moles of O2.
0. Hydrogen doesn't "reackt" to form Nitrogen Monoxide.
The balanced chemical equation for the reaction between oxygen (O2) and hydrogen sulfide (H2S) is: 2H2S + 3O2 -> 2SO2 + 2H2O From the equation, it is a 3:2 ratio of O2 to H2S. Therefore, if 2.3 moles of H2S are present, (2.3 moles H2S) * (3 moles O2 / 2 moles H2S) = 3.45 moles of O2 are needed.
16,875 moles of oxygen are needed.
For the reaction of propane (C3H8) with oxygen (O2), the balanced equation is: C3H8 + 5O2 -> 3CO2 + 4H2O. This means that 5 moles of O2 are required to react completely with 1 mole of propane (C3H8). Therefore, to react completely with 4 moles of propane, you would need 20 moles of O2.
The balanced chemical equation for the reaction between ammonia (NH3) and oxygen (O2) is 4NH3 + 3O2 → 2N2 + 6H2O. From the equation, we can see that 3 moles of O2 are needed to react with 4 moles of NH3. This means the molar ratio of O2 to NH3 is 3:4. First, calculate the number of moles of NH3 in 200.0 g: 200.0 g NH3 / 17.03 g/mol NH3 = 11.75 moles NH3 Now, calculate the number of moles of O2 needed using the molar ratio: 11.75 moles NH3 * (3 moles O2 / 4 moles NH3) = 8.81 moles O2 Finally, convert moles of O2 to grams: 8.81 moles O2 * 32 g/mol O2 = 282.0 g O2.
0,5 moles Cl-
The balanced equation shows that 2 moles of H2S react with 3 moles of O2. Therefore, to react completely with 2.3 moles of H2S, you would need (3/2) x 2.3 moles of O2 which is equal to 3.45 moles of O2.
1 mole
The balanced equation is C3H8 + 5O2 ---> 3CO2 + 4H2O moles C3H8 = 23.7 g x 1 mol/44 g = 0.539 moles moles O2 needed = 5 x 0.539 moles = 2.695 moles O2 (it takes 5 moles O2 per mole C3H8) grams O2 needed = 2.695 moles x 32 g/mole = 86.2 grams O2 needed (3 sig figs)