The solution is 0,25 M.
Molarity = moles of solute/Liters of solution Find moles glucose, which is molecular formula------C6H12O6 154 grams C6H12O6 (1 mole C6H12O6/180.156 grams) = 0.8548 moles C6H12O6 Molarity = 0.8548 moles C6H12O6/1 Liter = 0.855 M glucose ---------------------------
Molarity = moles of solute/Liters of solution Molarity = 5 moles solute/4.5 Liters of solution = 1 M solution ==========
The number of moles of solute will not change. Too, the molarity of the solution decreases.
The molarity of a solution is the number of moles of a solute per liter of its solution. The normality of a solution is the number of gram equivalent weight of a solute per liter of its solution. As I said before, and precisely, Molarity is moles of solute per VOLUME of solution!
Find moles of glucose. 32.8 grams C6H12O6 (1 mole C6H12O6/180.156 grams) = 0.18206 moles C6H12O6 Molarity = moles of solute/Liters of solution M = 0.18206 moles C6H12O6/1.0 L = 0.18 M C6H12O6
The answer is of course 6 moles.
I need this too. I've read that it may be the Van't Hoff factor.
Molarity = moles of solute/Liters of solution Find moles glucose, which is molecular formula------C6H12O6 154 grams C6H12O6 (1 mole C6H12O6/180.156 grams) = 0.8548 moles C6H12O6 Molarity = 0.8548 moles C6H12O6/1 Liter = 0.855 M glucose ---------------------------
Molarity = moles of solute/Liters of solution Molarity = 5 moles solute/4.5 Liters of solution = 1 M solution ==========
You mean solution right, not solutipon? lolIt is called the van't Hoff factor (i)
You need to know the moles of solute and the VOLUME of SOLUTION.
The concentration in moles of a substance in the solution
Molarity= No. of moles of solute/Volume of solution(in litre) or No. of moles of solute*1000/Volume of solution(in ml)
The number of moles of a solute per kilogram of solvent. (Apex)
The molarity of a solution containing 7.0 moles of solute in 569mL of solution is a)81M b)0.081M c)12M D)4.0M The answer is C. 12M 7 x 1000/569 = 12.302
The number of moles of solute will not change. Too, the molarity of the solution decreases.
moles of solute over kg of solvent