See the Related Question "How do you solve Ideal Gas Law problems?" to the left for the answer.
25 moles of sulfur dioxidecontain 800,825 g oxygen.
3.82g of SO2 equals 0,06 moles.
The formula mass of the compound sulfur dioxide, SO2 is 32.1 + 2(16.0) = 64.1Amount of SO2 = mass of pure sample/molar mass = 37.4/64.1 = 0.583mol There are 0.583 moles of sulfur dioxide in a 37.4g pure sample.
1.2 Moles
The maximal mass is 30 moles sulfur dioxide.
Four moles of sulfur dioxide would consist of how many molecules?
25 moles of sulfur dioxidecontain 800,825 g oxygen.
3.2 moles
composition stoichiometry.
3.82g of SO2 equals 0,06 moles.
800 g oxygen are needed.
1.6*avagardo constant Avagardo constant=6.022*10^23
Sulfur has relative atomic mass of 32 and oxygen have that of 16. The molar mass of sulfur dioxide is 64 grams per mole. Therefore there is approximately 0.58 moles (37.14/64) of sulfur dioxide in given weight.
The most straightforward reaction for the formation of SO3 from SO2 is 2 SO2 + O2 => 2 SO3. If this is the actual reaction for the formation, 3 moles of SO3 are formed from 3 moles of SO2.
The formula mass of the compound sulfur dioxide, SO2 is 32.1 + 2(16.0) = 64.1Amount of SO2 = mass of pure sample/molar mass = 37.4/64.1 = 0.583mol There are 0.583 moles of sulfur dioxide in a 37.4g pure sample.
1.2 Moles
1.2 Moles