Zinc and hydrochloric acid
3
323.2 grams of KO2 is equal to 4.55 moles of KO2. Per the equation, 3.4125 moles of O2 is produced which is equal to 2.055 E24 molecules of oxygen. This means that every mg of KO2 produces 6.36 E18 molecules of O2.
no
CO2
CO2
3
Calcium (Ca) is element. O2 and CaO are molecules.
323.2 grams of KO2 is equal to 4.55 moles of KO2. Per the equation, 3.4125 moles of O2 is produced which is equal to 2.055 E24 molecules of oxygen. This means that every mg of KO2 produces 6.36 E18 molecules of O2.
no
I am presuming that you are asking how many carbon dioxide (CO2) molecules will be formed when two ethane (C2H6) molecules burn in a plentiful supply of oxygen. The following balanced equation is that of the burning of ethane in a plentiful supply of oxygen: C2H6 + 3.5O2 -----> 2CO2 + 3H2O. The number before each of the molecules in the equation tells us how many there are in this reaction. This means that for every one ethane molecule that is burnt, two carbon dioxide molecules are produced.
It is the amount of energy consumed per unit of time.
CO2
CO2
The equations of molecules are: the centrificle force of the armpitists is the san granada of the melecular chopo grumka chopochita
Please post the equation
Solve the following equation for A : 2A/3 = 8 + 4A
To determine the mass of ammonia consumed, we need the balanced equation for the reaction. Without that information, we cannot accurately calculate the amount of ammonia consumed by the reaction of g of oxygen gas.