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a 3/4 ton Chevy pickup with a 350 gets 15mpgs, at best, 8-10 worst
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∙ 12y ago
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What proportion of cars with a mean fuel usage of 57 miles per gallon and a standard deviation of 3.5 mpg and the mpg is approximately normally distributed get between 57 and 62 mpg?
z = (x - mean_x)/standard_deviation → z = (62 - 57)/3.5 = 1.43 Looking up z = 1.43 in normal tables gives a value of 0.4236 which is the probability that the value lies between 57 and 60. The probability of getting between 57 and 62 mpg is approx 42.36 %
How mush HP is in a 1991 350 57?
It can be from 180 h.p. (Base Engine) to 375 h.p. (Corvette) depending on which 1991 5.7 liter engine you are talking about. You did not specify which 350, so you get no definitive answer.
What proportion of cars with a mean fuel usage of 57 miles per gallon and a standard deviation of 3.5 mpg and the mpg is approximately normally distributed get over 60 mpg?
z = (x - mean_x)/standard_deviation → z = (60 - 57)/3.5 = 0.88 Looking up z = 0.88 in normal tables gives a value of 0.3106 which is the probability that the value lies between 57 and 60, so the probability of it being greater than 60 is 0.5 - 0.3106 = 0.1894 = 18.94 % The probability of getting greater than 60 mpg is approx 19%
How many multiplication problems are in the number 57?
Infinitely many: 57*1 57*2 57*2.1 57*2.2 and so on, and on, and on.
Where is the fuel pump located on a 1989 Chevy 2500 4x4 with a 57 liter?
in the fuel tank.
What proportion of cars with a mean fuel usage of 57 miles per gallon and a standard deviation of 3.5 mpg and the mpg is approximately normally distributed get less than 45 mpg?
z = (x - mean_x)/standard_deviation → z = (45 - 57)/3.5 = -3.43 Being negative, it shows it is less than the mean; only the absolute value needs to be considered Looking up z = 3.43 in normal tables gives a value of 0.4997 which is the probability that the value lies between 45 and 57, so the probability of it being less than 45 is 0.5 - 0.4997 = 0.0003 = 0.03 %, The probability of getting less than 45 mpg is approx 0.03%
What proportion of cars with a mean fuel usage of 57 miles per gallon and a standard deviation of 3.5 mpg and the mpg is approximately normally distributed get 51 mpg or less?
z = (x - mean_x)/standard_deviation → z = (51 - 57)/3.5 = -1.71 Being negative, it shows it is less than the mean; only the absolute value needs to be considered Looking up z = 1.71 in normal tables gives a value of 0.4564 which is the probability that the value lies between 51 and 57, so the probability of it being less than 51 is 0.5 - 0.4564 = 0.0436 = 4.36 % The probability of getting less than 51 mpg is approx 4.36 %
What engine company is in Karen kingsbury's book one Tuesday morning?
engine 57
Where is the fuel pump located in the gas tank on a 1997 Chevrolet Express van 57 liter engine?
drop the gas tank remove the float/pump assy. and the pump is the silver cylinder had one replaced by a dealer expensive
How much does a lamda sensor cost for a Renault megane scenic?
ive just had one fitted by a garage ,the part cost £57 ,fitting cost around £30 gulp! Was an MOT fail because it messes up the emmissions badly, a knackered sensor causes the engine management system to run the engine rich with poor mpg
How do you find out how much gas you will need for a trip?
Take the MPG that the vehicle will average divided into the miles you are going to travel. This will tell you how many gallons of fuel you will need. Example: 25 MPG on a 500 mile round trip will require 20 gallons of fuel. At 2.85 per gallon this trip will cost you $57 in fuel costs.
How many mils is 57 grams?
57 grams of water is 57 ml.
