The address lines A0..A15 are multiplexed with the data lines D0..D15 on the pins AD0..AD15
There are 16 data lines in 8086.
8086 have 5 interrupt lines.
There are 20 address lines and 16 data lines in the 8086 microprocessor. The low order 16 address lines are multiplexed with the data lines. Some of the high order address lines are multiplexed with status lines.
There are eight datalines, D0 through D7, in the 8085 microprocessor. They are shared, or multiplexed with the eight low order address lines, A0 through A7, and are called AD0 through AD7 on the pinout drawing.
The 8086/8088 has 20 address lines. It can access 220, or 1MB, or 1,048,576 bytes of memory.
The 8086/8088 has 20 address lines. It can access 220, or 1MB, or 1,048,576 bytes of memory.
8086 is a 16- bit microprocessor. It has 20-bit address bus. It has 14 16-bit registers. It has multiplexed address and data bus. It provides 33% duty cycle. 8086 supports multiprogramming. It is designed to operate in two modes, i.e. min and max. you can download the simulation program(for running your programs on your computer) at - http://www.ziddu.com/download/15018415/emu_8086.zip.html
10
8086 has 20 address lines. Therefore it can address 220 bits or 1,048,576 bits of memory, or roughly 1 MB (mega byte).
The 8086 family of microprocessors, including the 8086, 80C86, and 80C86AL, are presented in 40-pin DIP packages.
You need 3 8282 latches because there are 20 address lines, not 16. A16, A17, A18, and A19, are also multiplexed with S3, S4, S5, and S6. Also, BHE- is multiplexed with S7. You can eliminate one latch if the system memory is small.
There are two hardware interrupts in the 8086/8088. INTR, which is maskable, and NMI, which is not.