How many n's are there in an atom of p-33?

Answer 1

The answer is 15 p electrons

You first need to figure out which orbitals are filled.

This is an old trick my High-school teacher taught me. Using this arrangement and going in diagonal from top-right to bottom-left tells you the order in which orbitals are filled.

∕

1s ∕ ∕

2s 2p ∕ ∕

3s 3p 3d ∕

4s 4p 4d

5s 5p 5d

This translate in:

1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, ect...

All that's left is counting the number of electrons per orbital.

s, p and d are the orbitals with this maximum number of electron each.

s=2, p=6, d=10

As such, counting up to 33 is

1s 2s 2p 3s 3p 4s 3d 4p

2+2 +6 +2 +6+2+10+(3) = 33 (p electrons are in Bold)

Answer 2

One electron is 1,602*10^-19 Coulomb

1,602*10^-19 Coulomb --> 1e

1 coulomb --> 1 e / 1,602*10^-19

33Coulombs --> 1e / 1,602*10^-19 * 33

= 2,06 * 10^20 electrons

Answer 3

Phosphorous has an atomic # of 15, which means it has 15 protons.

P-33 has an atomic weight of 33 (hence the name).

The atomic weight of an element is the # of neutrons + # of protons.

n + p = w

n + 15 = 33

n = 18

Answer 4

30