I have 24 and I have 6 nesting boxes. They share, and a lot of the time they wont even use one
27
27+73=100 You need to add 73 to 27 to get 100.
On this farm there would be a total of 18 cows. There would also be 18 chickens, combining to make 36 heads and 104 legs.
Here's a Perl script that will answer the problem for any number of heads and feet. sub how_many { print "Number of heads: "; chomp($h = ); print "Number of feet: ";chomp($f = ); $p = $h; $c = 0; while (($p*4 + $c*2) != $f) { $p--; $c++; } } &how_many; print "There are $p pigs and $c chickens.\n"; print "They have $h heads and $f feet.\n"; Number of heads: 27 Number of feet: 78 There are 12 pigs and 15 chickens. They have 27 heads and 78 feet.
You need 27 Box of 9 tiles
27/35
1
From the information given, none of them need be red!
Nine in each square foot. (27 times 9 equals 243).
There are 21 three-legged cows and 27 chickens on the farm. Let us say the number of cows = A and the number of chickens is B. The equation for heads is: A+B = 48 The equation for legs is: 3A + 2B = 117 (because a cow has 3 legs and a chicken has 2 legs in this question) We can rearrange the equation for heads as follows: A+B = 48 B = 48-A Now we can replace B in the equation for legs with 48-A as follows: 3A + 2(48-A) = 117 ...and solve: 3A + 96 - 2A = 117 A + 96 = 117 A = 21 So we know there are 21 three-legged cows and from earlier, B = 48-A, so B = 48-21 = 27. Therefore there are 27 chickens.
that would be about 10 pounds
1050/27 = 38-8/9 gallons = 38.88889 (rounded)