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On a farm there are horses and chickens there are a total of 27 heads and 92 legs how many horses are on the farm?
27
How many do you need to add if you have 27 and you want to make 100?
27+73=100 You need to add 73 to 27 to get 100.
How many 27 bicycle tires do you need for your upcoming cycling trip?
You will need two 27-inch bicycle tires for your upcoming cycling trip.
There are 78 feet 27 heads how many pigs and chickens?
Here's a Perl script that will answer the problem for any number of heads and feet. sub how_many { print "Number of heads: "; chomp($h = ); print "Number of feet: ";chomp($f = ); $p = $h; $c = 0; while (($p*4 + $c*2) != $f) { $p--; $c++; } } &how_many; print "There are $p pigs and $c chickens.\n"; print "They have $h heads and $f feet.\n"; Number of heads: 27 Number of feet: 78 There are 12 pigs and 15 chickens. They have 27 heads and 78 feet.
In a barn there are some chickens and pigs there are 11 heads and 36 legs how many chickens and pigs are there?
On this farm there would be a total of 18 cows. There would also be 18 chickens, combining to make 36 heads and 104 legs.
How many 16x16 tiles would you need for 242sq ft?
You need 27 Box of 9 tiles
How many marks do you need to pass gcse french listening?
27/35
On pet society on Facebook how many paw points do you need to have to be level 27?
1
How many times will 27 go into 243?
To determine how many times 27 will go into 243, you need to divide 243 by 27. The result of this division is 9, meaning that 27 will go into 243 nine times without any remainder. This is because 27 multiplied by 9 equals 243.
How many times does 27 go into 108?
To determine how many times 27 goes into 108, you need to divide 108 by 27. The result of this division is 4, which means that 27 goes into 108 exactly 4 times without any remainder. So, 27 goes into 108 four times.
On a farm there are three-legged-cows and chickens There are total of 48 heads and 117 legs How many three-legged-cows are on the farm?
There are 21 three-legged cows and 27 chickens on the farm. Let us say the number of cows = A and the number of chickens is B. The equation for heads is: A+B = 48 The equation for legs is: 3A + 2B = 117 (because a cow has 3 legs and a chicken has 2 legs in this question) We can rearrange the equation for heads as follows: A+B = 48 B = 48-A Now we can replace B in the equation for legs with 48-A as follows: 3A + 2(48-A) = 117 ...and solve: 3A + 96 - 2A = 117 A + 96 = 117 A = 21 So we know there are 21 three-legged cows and from earlier, B = 48-A, so B = 48-21 = 27. Therefore there are 27 chickens.
How many red cubes does a 27 c cube have?
From the information given, none of them need be red!
