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A bromine atom has 7 half-filled orbitals: one in the 4s orbital, three in the 4p orbitals, and three in the 4d orbitals.
17. The electronic configuration of bromine is 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 4p5
The bromine atom in BrF5 has sp3d2 hybridization. This means that it has one 3s, three 3p, and two 3d orbitals that combine to form six equivalent sp3d2 hybrid orbitals.
In BeBr₂, the central beryllium atom forms two sigma bonds with the bromine atoms. The overlapping orbitals involved in these sigma bonds are the sp³ hybrid orbitals of beryllium and the p orbitals of the bromine atoms. Beryllium undergoes hybridization to create two equivalent sp³ orbitals, which then overlap with the p orbitals of each bromine atom, resulting in the formation of two Be-Br sigma bonds.
The central atom in BrCl3 is bromine (Br). The bromine atom in BrCl3 adopts sp3d hybridization, which involves the mixing of one 4s, three 4p, and one 4d atomic orbitals to form five sp3d hybrid orbitals.
In the formation of the bromine (Br₂) molecule, the overlapping orbitals are the p orbitals of the two bromine atoms. Specifically, the 4p orbitals from each bromine atom overlap to form a sigma bond, resulting in the diatomic molecule. This overlap allows for the sharing of a pair of electrons, which is essential for bond formation.
The last orbital to fill in a bromine atom is the 4p orbital. Bromine has a total of 35 electrons, with the electron configuration of [Ar] 4s2 3d10 4p5. The 4p orbital can hold a maximum of 6 electrons.
* Ground state electron configuration:[Ar].3d10.4s2.4p6 so...4s and 4p
A neutral bromine atom has 35 electrons.
the answer is 3
1s22s22p6
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